I did read this section, but it is 100% clear to a new user that the 'automatic' nature is the isAjax function works only if you are using prototype.js. I'm sure it says something about this somewhere, but I did not see it in the controller section of the docs, so I was just making sure I understood how to do the same thing with jquery.
On Jul 9, 1:34 am, "Dr. Tarique Sani" <[EMAIL PROTECTED]> wrote: > On 7/8/07, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > > > Or, do I just create an empty layout and use it to return my snippets > > of html with ajax > > http://manual.cakephp.org/chapter/request_handlersection 4 describes a > solution to your problem > > @sTb who fooled you into thinking that the F in RTFM stood for f**king ? :D > > HTH > T > > -- > ============================================================= > Cheesecake-Photoblog:http://cheesecake-photoblog.org > PHP for E-Biz:http://sanisoft.com > ============================================================= --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Cake PHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
