Depends how you update you select box with your code, I think FireFox need to replace the complete select.
Look here, I think it's mentioned somewhere : http://www.devmoz.com/blog/2007/04/04/cakephp-update-a-select-box-using-ajax/ On Oct 2, 10:41 pm, Lir <[EMAIL PROTECTED]> wrote: > Hello I want to submit a form that has a select which was updated > using ajax.updater > My Ajax.updater works fine. The problems is that in FIREFOX don't > recognize or don't get the name of the select tag and don't submit the > value or option. > Inside the form I have a <Div> where ajax.updater will replace the > select results. Once it's updated I submit the form but the select > information isn't post. at least it works fine in IE > Thanks in advance for any help. This is the code > > HTML > <form enctype="multipart/form-data" name="uploadt" method="post" > action="' . $form_action . '" "> > <tr><td>Loss Seq</td> > <td><div id="lossResult"> > <select name="temp"><option></option></select> //AJAX > RESULT HERE > </div> > </td></tr> > </form> > > NEW SELECT - AJAX UPDATER > echo "<select name='submit_loss' class='upload'>"; //IT LOOKS GOOD BUT > IT'S NOT SUBMITTED > echo "<option value='000' ></option>"; > foreach ($return as $row) > { > echo "<option value='$row[LOSS]' selected>$row[LOSS]</ > option></br>"; > } > echo"</select>"; > > AFTER I SUBMIT EVERYTHING I WANT TO DISPLAY THE $_POST[SUBMIT_LOSS] > that right now I don't see it . Something > like that > <tr> > <td>Loss Sequence Numbers:</td> > <td>'.$_POST['submit_loss'].'</td>//NOTHING APPEAR HERE > </tr> --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Cake PHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
