1. Add $primaryKey = 'zip'; in Zipcode model.
2. Define 'foreignKey'=>'zip' in $hasMany association.
3. Your associations should looks like: User belogsTo Zip, Zip hasMany
Users.
On Dec 4, 9:02 am, Jon Hinson <[EMAIL PROTECTED]> wrote:
> Ok, I can't seem to solve this problem for the life of me. I have a
> User model and a Zipcode model. Zipcode hasMany users. I want them to
> join on User.zip = Zipcode.zip. I have to join on Zipcode.zip and not
> Zipcode.id because a zipcode can have many rows because of several
> city names, etc. I know this is not normalized, but it is much easier
> like this. So I have a hasMany association that looks like this:
>
> var $hasMany = array('User' =>
> array('className' => 'User',
> 'conditions' => '',
> 'order' => '',
> 'dependent' => true,
> 'foreignKey' => '',
> 'finderQuery' => '
> SELECT *
>
> FROM users as User
>
> JOIN zipcodes as Zipcode ON (User.zip = Zipcode.zip)'
> )
> );
>
> I tried using the finderQuery after doing foreignKey => 'zip' didn't
> work. I also had a belongsTo Zipcode in User with foreignKey =>
> 'zip' :
>
> var $belongsTo = array('Zipcode' =>
> array('className' => 'Zipcode',
> 'conditions' => '',
> 'order' => '',
> 'dependent' => true,
> 'foreignKey' =>
> 'zip'
> )
> );
>
> With everything that I've tried, when I do a $this->Zipcode->User->findAll,
> or try to paginate with $this->Zipcode->User, it tries to
>
> join on User.zip = Zipcode.id instead of Zipcode.zip.
>
> Any help is much appreciated.
> Jon
>
> PS- I'm using Cake 1.2
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