I have an input file html element in my form.
<?php echo $form->file('Flyer.file',
array('label'=>__('flyer.file.label', true))); ?>
Then I need to proccess it
function upload() {
(...Code...)
elseif(!empty($this->data)){
if ($this->data['Flyer']['file']) {
list($width, $height) =
getimagesize($this->data['Flyer']
['file']);
print_r($this->data['Flyer']
['file']); //This is for debugging purposes.
(...Code...)
}
However, it (print_r) prints just the filename (i.e flyer_test.jpg).
I was expecting that:
$this->data['Flyer']['file'] = array ('name' => 'FooName.jpg', 'type'
=> 'MimeType', 'tmp_name' = '/tmp/Foo', 'error' => Value, 'size' =>
Value)
Why it just throws $this->data['Flyer']['file'] = "flyer_test.jpg"
Any help is appreciated. Thanks.
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