hi, That's indeed a possibility, i just figured out myself too. I now have a AJAX call to a controller, which displays a view without a layout in which the element is rendered. I thought this had to be easier to do, because the view is almost empty and i have to manually turn the layout off.
is there really no shorter way? On 18 mei, 17:30, aranworld <[EMAIL PROTECTED]> wrote: > I'm not sure why you would need to render an element from within a > controller? As far as I know this is not the intended purpose of > elements. > > If this is a controller method called via AJAX then I believe you > should be rendering a "view". > > In the view file, you then include the element you want to render. > > On May 18, 3:52 am, UGn <[EMAIL PROTECTED]> wrote: > > > Hi there, > > > I'm really stuck on a (i guess it's a simple) thing and i would really > > appreciate > > someone helping me with it.. > > > The problem is: > > > I have an element which renders the first productimage belonging to a > > product and the navigation to the next images (with AJAX links). > > To update this element i need some params (photo_data, new photo_id, > > and product_id (for navigation)). > > > But from my controller i cannot use renderElement so i use: > > > $this->render(null,'ajax',DS.'elements'.DS.'productimage_view'); > > > so how can i get my params with this render? > > > thnx in advance, > > > UGn --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
