You should probably set $this->displayField variable in your model (ie.. var $displayField = 'user_name';). I've written a bit about it at http://php.abdullahsolutions.com/2008/02/what-will-you-find.html.
Hope that helps. On 6/3/08, Mee <[EMAIL PROTECTED]> wrote: > > Hello everyone! > > I have a model with a foreign key, that links it to another model. > Can you tell me how to make listbox with the field from another model, > instead of it's id in current model? > > (i.e. user_name instead of user_id) > > thanks in advance, > mee > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
