Because I love this community and I want to help nexts with this
problem...
Don't try to update two fields...

A good solution is use javascript code function, using the complete
trigger;

<?php echo $ajax->form('/comments/add', 'post', array( 'url' => '/
comments/add', 'update' => 'feed','complete'=>"update2divs()" /
*'indicator' => 'commentSaved'*/));?>


On complete I call my function called update2divs

In my file of javascript i have this function:


function update2divs() {

new Ajax.Updater('PostsComments', root + '/tests/hello',
{ method: 'post',
  insertion: Insertion.Bottom });

}

Interesting solution...
Because I can call my function and append the html in bottom or top...

The root is a general var, because, i have my root site in
subfolder...and when you upload in your site...
THat all...
So I can update my div, and give feedback to user of some error...and
if completed succefully the request...
I append the data to the div...without refreshing all the page.. but
simply append the data...

I cannot immagine a better solution, considering not spending
resources in the server...

So if you want to complete the cake, it would be interesting to put
focus on the div...but i have read that exists some problem with
different browser....

Good job...






On 12 Giu, 17:42, Alessio <[EMAIL PROTECTED]> wrote:
> <?php echo $ajax->form('/comments/add', 'post', array( 'url' => '/
> comments/add', 'update' => 'feed', 'indicator' => 'commentSaved'));?>
>
> I tried many option to update more div...
> for example putting 'update' =>array.....
> But is it possible?
>
> How can I to say to cake to create two update div?
> In one, I need show the comments...
> And in the other div I need to show the message "saved" or "error";
>
> I can use also javascript:
>
> function update2divs(parameters) {
>     ajaxupdate('div1','url');
>     ajaxupdate('div2','url2');
>
> }
>
> But How can I call this function, using $ajax->form?
>
> Another question, how can I move the focus on a div...I need to show
> the comment when the user has finished posting the comment.
>
> Very thanks.
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