I'm quite interested in this as well. Can you tell us more about how
you made this work, maybe show your code?
My problem is that I "disappear" my form after data is submitted. Can
I somehow "not disappear it" when it doesn't validate?
/Anders
On Nov 11, 8:51 am, Bart <[EMAIL PROTECTED]> wrote:
> I just found it.
> I needed to ALSO make the AJAX call update the form.
>
> On 10 nov, 22:17, Bart <[EMAIL PROTECTED]> wrote:
>
> > Hello there,
>
> > I have aformthat I submit with anAJAXcall. TheAJAXcall also
> > updates another div in the page. I does not update theformdiv
> > itself.
> > All goes well, except when theforminput is validated as false there
> > is no error message.
> > The submission simply stops, the item is not inserted into the
> > database and a new submit attempt can be made.
>
> > When I do the submission by a regular POST call (noAJAX), I do get
> > the right error message.
> > Is there a workaround?
> > Theajaxformcode looks as follows:
>
> > echo $ajax->form('Snack', 'POST', array('update'=>'centralText',
> > 'url'=>'/updateSnack', 'before'=>'togglePreloader();',
> > 'complete'=>'togglePreloader();'));
>
> > Thanks,
> > Bart
>
>
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