It works:
function beforeFilter()
{
parent::beforeFilter();
$this->Auth->authError = sprintf(__('You are not authorized to
access that location %s .',true),$this->name.'-'.$this->params['action']);
}
Gives me:
"You are not authorized to access that location Hotelmasters-index"
Anja
-----Ursprüngliche Nachricht-----
Von: [email protected] [mailto:[email protected]] Im Auftrag
von Liebermann, Anja Carolin
Gesendet: Montag, 15. Dezember 2008 11:57
An: [email protected]
Betreff: AW: Debugging Auth: getting the name of teh action I get kicked
Hi,
That looks promising, I will try that out.
Anja
-----Ursprüngliche Nachricht-----
Von: [email protected] [mailto:[email protected]] Im Auftrag
von gearvOsh
Gesendet: Freitag, 12. Dezember 2008 23:06
An: CakePHP
Betreff: Re: Debugging Auth: getting the name of teh action I get kicked
Or check the $this->params, I believe its $this->params['action'];
On Dec 12, 7:06 am, Daniel Hofstetter <[email protected]> wrote:
> Hi Anja,
>
> > I get kicked out of some actions in some controllers. I have alread
> > placed function beforeFilter()
> > {
> > parent::beforeFilter();
> > $this->Auth->authError = sprintf(__('You are not
> > authorized to access that location %s .',true),$this->name);
> > }
>
> > Which gives me at least the controller name.
> > How can i get the name of the action which I am not authorized to see?
> > Is there a possibility to get it shown on page?
>
> > Mind: I have about 700 actions so something which I haven't to add
> > to each action would be ideal.
>
> $this->action should do the trick.
>
> --
> Daniel Hofstetterhttp://cakebaker.42dh.com
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