Hey, maybe a stupid question, but i'm stuck.
i want to create a link with this output:
a onmouseout="mymouseout()" onmouseover="mymouseover(0)"
href="...">Marker One</a>
i tried this with this:
<?php echo $html->link($article['article']['name'], '/articles/view/'.
$article['article']['id'], array('onmouseover' => 'alert(\"test\")'));?
>
but the function is always in " ".
how can i get a link with a working call to a javascript function!?
Thanks for your help!
greetings!
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/cake-php?hl=en
-~----------~----~----~----~------~----~------~--~---