The complicating factor here is that Aliquot belongs to Specimen in my model and I want to display some information from both tables: Specimen.type, Specimen.draw_date, Aliquot.additive & etc. It looks more and more like I'm going to have to put that information in an array and loop through it, building each checkbox one at a time instead of my example below. Or am I missing something?
On Jan 15, 11:01 am, grigri <[email protected]> wrote: > You need to set the $displayField property inside your `Aliquot` model > to whatever field you want for the label. > > On Jan 15, 4:47 pm, Tony Thomas <[email protected]> wrote: > > > I'm building a list of checkboxes like so: > > > echo $form->input('Aliquot.id', array( 'label' => FALSE, > > > > 'type' => 'select', > > > > 'multiple' => 'checkbox', > > > > 'options' => $aliquots)); > > echo $form->input('box_id', array('options' => $boxes)); > > > $aliquots above is built from $this->Aliquot->find('list', $options); > > which finds all the ids of the pertinent records. The problem I have > > this this only generates a list of ids. Is there good way to load an > > array for 'label' so that I can display more than just the list of ids? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
