Thanks for the reply mscdex

I think if you do it the way I posted (put the field in Tag) you don't
need bindModel at all. You can also use save() and not saveAll().

On Mar 5, 2:28 am, mscdex <[email protected]> wrote:
> On Mar 4, 6:52 pm, Omi <[email protected]> wrote:
>
> > The correct way is to set
> > $this->data['Tag'][0] = array(
> >                                            'tag_id' => $foo,
> >                                            'tagger_id' => $bar
> >                                          );
>
> This is kinda on the right track. Here's an example of what I used for
> a Movies sample project:
>
> views/movies/add.ctp:
> <?php
> echo $form->create('Movie');
> echo $form->input('Movie.name');
> echo $form->input('MoviesUser.0.user_id');
> echo $form->input('MoviesUser.0.ranking');
> echo $form->end('Submit');
> ?>
>
> controllers/movies_controller.ctp:
>         function add() {
>                 if (!empty($this->data)) {
>                         $this->Movie->create();
>                         
> $this->Movie->bindModel(array('hasMany'=>array('MoviesUser')),
> false);
>                         if ($this->Movie->saveAll($this->data)) {
>                                 $this->Session->setFlash(__('The Movie has 
> been saved', true));
>                                 $this->redirect(array('action'=>'index'));
>                         } else {
>                                 $this->Session->setFlash(__('The Movie could 
> not be saved. Please,
> try again.', true));
>                         }
>                 }
>                 $users = $this->Movie->User->find('list');
>                 $this->set(compact('users'));
>         }
>
> IIRC the key was to do a bindModel with the name of the join relation
> name as a hasMany association before saving.
>
> Hope that helps some.

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