<?php echo $javascript->link(array('prototype')); ?>
Works for me.
On Apr 29, 4:22 pm, "[email protected]" <[email protected]> wrote:
> Hi,
>
> When I was using the older version of cakephp, I was using javascript
> in a view this way:
>
> <?php echo $javascript->link('util'); ?>
>
> In the version 1.2, it doesn't work. What is the sintax I have to use?
>
> Regards,
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