$(document).ready(function() {
$('#UserUpdateForm').bind('submit', function() {
var numRand = Math.floor(Math.random()*100000);
var queryString =
$('#UserUpdateForm').formSerialize();
$(this).ajaxSubmit({
type: 'post',
url:
'/joesmith/update/systems/' + numRand ,
data: queryString,
target: '#systems',
//success: function()
{$(this).fadeOut("slow")}
});
return false; // <-- important!
});
});
-----Original Message-----
From: Miles J [mailto:[email protected]]
Sent: June-03-09 12:53 AM
To: CakePHP
Subject: Re: Security Component and AJAX
Can I see your js ajax code.
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