On Thu, Jun 11, 2009 at 11:06 AM, Nancy<[email protected]> wrote:
>
> Ok, I understand that. Thanks for the explanation. So it almost sounds
> like I need to either have the events external to the tags or else I
> need some code to evaluate the javascript in the tags (I found a pure
> javascript example). But where would I put that code? In my main
> page or inside the Ajax rendered view? Hmmm... maybe it doesn't
> matter.
You can create a function which sets your event handlers on certain
elements. Call this on page load as well from your AJAX 'success'
callback.
> I think from my experiments I determined that code inside the <script>
> tags was getting evaluated. But why isn't the $javascript->link
> ('filename') tag getting loaded I wonder?
>
> On Jun 10, 6:27 pm, brian <[email protected]> wrote:
>> On Wed, Jun 10, 2009 at 4:02 PM, Nancy<[email protected]> wrote:
>>
>> > Something seems to happen when you have javascript embedded in an ajax
>> > rendered view and it is getting me confused!
>>
>> > I have this line at the top, it works when I call the view directly,
>> > but doesn't seem to do anything when ajax renders the view:
>>
>> > <?= $javascript->link('clearSelect'); ?>
>>
>> > I see the alerts when the page is loaded directly but not through
>> > ajax. The function works ok when loaded directly but not through
>> > ajax. I'm using Protype and Ajax.
>>
>> > ====== clearSelect.js ==============
>> > alert("hello!");
>> > function unselectAll(ele)
>> > {
>> > alert(ele);
>> > var obj=$(ele);
>> > for (var i=0; i < obj.options.length; i++)
>> > {
>> > obj.options[i].selected = null;
>> > }
>> > }
>> > =============================
>>
>> > I've also run into this issue when I have buttons and things on my
>> > form I try to put some Javascript on, and they just don't work. I've
>> > googled for an answer and realize that perhaps events aren't getting
>> > hooked up but I'm not knowledgeable enough to figure out on my own how
>> > to address that. So any specifics would be hugely appreciated! And
>> > it looks like my javascript source file isn't being included at all.
>>
>> No, it is not. You have to understand what an AJAX request is, and
>> what your javascript function is doing with the result. In your case,
>> the view is being rendered by Cake into an HTML block which, when sent
>> back to the client, is inserted into the DOM. A javascript include is
>> not going to work because the tag will not be evaluated.
>>
>> It's a similar situation for event handlers. When the HTML chunk is
>> inserted int the DOM, if there's no instruction to evaluate the page
>> again in order to register event handlers you're not going to get the
>> expected results. I use jQuery, not Prototype, so I can't give you any
>> specifics to deal with that.
> >
>
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