I'm performing this in the Userpages controller. I was calling find on Users because I need information on the user's animal.
User hasMany Userpages User belongsTo Animal The foreign keys are set up appropriately. I need to get a list of all userpages in which: (Userpages.approved = 1) OR (Userpages.approved = -1 AND User.id/user_id = $id) But I want the following information: the Userpage id, the userpage user_id, and the frontfilename from the user's animal. The concept is similar to a list of comments: I want the id and contents of the comment, I want the information on the user, including the user's picture (in this case frontfilename which is a column in Animal). I suppose the catch is that more than one user can be the same animal (users are in groups). I've been searching everything that I can think of and searching based off what I find. Do you think the kind of join matters? I appreciate your following up and your help. Thank you, ~Sarah On Aug 30, 1:28 am, delocalizer <[email protected]> wrote: > Ah I hadn't realised you just wanted Userpages - in which case why not > call find on Userpage? > If you're in Users controller: > $pages = $this->User->Userpage->find('all',array( > 'conditions'=>array( > 'or'=>array( > 'approved'=>1, > 'and'=>array( > 'Userpage.approved' => -1, > 'user_id' => $id > ) > ) > ) > )) > > On Aug 30, 3:21 pm, Sarah <[email protected]> wrote: > > > Wow, this was very cool. Thank you for the advice. > > > I realized I had forgotten a condition. So this is where I am now: > > > $array = $this->User->find('all', array( > > 'fields'=>array('id', 'animal_id'), > > 'order'=>array('User.id'=>'asc'), > > 'contain'=>array( > > 'Animal'=>array( > > 'fields'=>array > > ('frontfilename') > > ), > > 'Userpage'=>array( > > 'conditions'=>array( > > 'or'=>array( > > 'approved'=>1, > > 'and'=>array( > > > 'Userpage.approved' => -1, > > > 'user_id' => $id > > ) > > ) > > ), > > 'order'=>array( > > 'id'=>'desc') > > ) > > ) > > ) > > ); > > > This does not cause any errors. :) However, I'm not quite sure that > > this is what I need. To my understand based of the reading on > > containable (and the results that I received from the query), this > > query will return all users and only return their userpage information > > if it matches the conditions. I suppose I could just check each user > > from the query to see if that user had any userpage info returned by > > the query, but I imagine this would slow things down? > > > I thank you very much for your time and help. I would appreciate any > > advice you can give. :) > > > Thanks, > > ~Sarah > > > On Aug 29, 1:08 am, delocalizer <[email protected]> wrote: > > > > Hi Sarah, > > > If you have a reasonably complicated find query with associated models > > > and conditions, the core 'Containable' behaviour is very > > > handy:http://book.cakephp.org/view/474/Containable > > > so in your AppModel put this (and all your models will have access to > > > the behaviour): > > > var $actsAs = array('Containable'); > > > then you would have for your query something like this: > > > $array = $this->User->find('all',array( > > > 'fields'=>array('id','animal_id'), > > > 'order'=>array('id'=>'asc'), > > > 'contain'=>array( > > > Animal=>array( > > > fields=>array('frontfilename') > > > ), > > > Userpage=>array( > > > 'conditions'=>array( > > > 'approved' => '1' > > > ), > > > 'order'=>array( > > > 'id'=>'desc') > > > ) > > > ) > > > )); > > > Note that conditions, fields and order options are all specified on a > > > per-model basis - you get back only what you want from each model. > > > Containable is definitely worth the effort to learn. > > > > cheers, > > > C. > > > > On Aug 29, 7:40 am, Sarah <[email protected]> wrote: > > > > > I fixed my syntax, > > > > > $conditions = array('or' => array( 'Userpage.approved' => 1, 'User.id' > > > > => $id) ); > > > > $order = array('User.id ASC', 'Userpage.id DESC'); > > > > $array = $this->User->find('all', array('fields'=>array('id', > > > > 'Userpage.id', 'User.animal_id', 'Animal.frontfilename'), > > > > 'conditions'=>$conditions, 'order'=>$order)); > > > > > but I'm still getting the same errors as before. > > > > > I verified that a User has many userpage and that a userpage belongs > > > > to a user. > > > > The SELECTing of the Animal picture is not a problem...I don't > > > > understand why it won't SELECT the userpage information... > > > > > My recursive level is set to 1, I tried setting it to 2, but it didn't > > > > make a difference. > > > > > Thanks for your time and help, > > > > ~Sarah > > > > > On Aug 28, 12:23 pm, WebbedIT <[email protected]> wrote: > > > > > > Looks like you very nearly had it. Just got your find syntax slightly > > > > > wrong, try: > > > > > > $array = $this->User->find('all', array( > > > > > 'fields'=>array('id, 'Userpage.id', 'User.animal_id', > > > > > 'Animal.frontfilename'), > > > > > 'conditions'=>$conditions, > > > > > 'order'=>$order > > > > > ); > > > > > > Then go have a look at the cookbook and study the syntax of the find > > > > > command a bit more. The first parameter should be the type of call, > > > > > in this instance 'all'. > > > > > > The second parameter needs to be an array with your fields, > > > > > conditions, order etc. > > > > > > Hope this helps --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. 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