And to do pagination? how can I do?
Thanks
On 1 Ott, 18:46, brian <[email protected]> wrote:
> On Thu, Oct 1, 2009 at 9:08 AM, byqsri <[email protected]> wrote:
>
> > Can someone help me about this?
>
> > On 7 Set, 09:13, "[email protected]" <[email protected]>
> > wrote:
> >> Hi
> >> I have this situation:
> >> I have a model Event and a model News , Both models have the field
> >> 'created' .
> >> Now in my view I would create a single list where there is there are
> >> both each others order by created.
> >> Example
>
> >> Event 1 07/09/09
> >> News 1 07/09/09
> >> News 2 06/07/09
> >> ......
> >> ......
> >> ......
>
> >> I would manage this list with paginate.
> >> Is someone can suggest me a pattern that I can use to do a thing like
> >> this?
> >> Many thanks
>
> I'm sure Set class can help with this. I had an idea but it's not
> quite there, I think.
>
> Say these are your data (inner arrays would all contain more key =>
> val, of course);
>
> $events = array(
> 'Event' => array(
> array('created' => '2007-10-02'),
> array('created' => '1998-02-03'),
> array('created' => '2001-04-30'),
> array('created' => '2002-05-23'),
> array('created' => '2003-07-21')
> )
> );
> $news = array(
> 'News' => array(
> array('created' => '2003-04-12'),
> array('created' => '2003-10-24'),
> array('created' => '2000-01-03'),
> array('created' => '2000-01-05'),
> array('created' => '2000-05-28')
> )
> );
>
> I'd think that this would do it:.
>
> $foo = Set::sort(
> Set::merge($events, $news),
> '{s}.{n}.created', 'desc'
> );
>
> But that returns an empty array.
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