Thank you, but that isn't working for me. I have a link that retrieves some data and populates a div with an element. With Javascript disabled I just get the contents of the element in an otherwise blank screen. What I want to do is something like this:
If (javascript is enabled): show this link else show another link end if So what I am looking for is a nifty little piece of code to do the "if javascript is enabled" bit. On Dec 10, 5:27 pm, "Dr. Loboto" <[email protected]> wrote: > AJAX links and forms in Cake AJAX helper has fallback. If JS is not > enabled links/forms will work as normal ones. > > On Dec 10, 6:58 pm, Jeremy Burns <[email protected]> wrote: > > > > > I want to use the Ajax helper when Javascript is enabled, but revert > > to the plain old ordinary html helper when it is not. How can I do a > > simple test to see if Javascript is enabled? Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
