Why are you using two ids?
<?php echo $form->create('User', array('action'=>'check', 'id'=>
$formid, 'name'=>$formid, 'id' => $submitid)); ?>
I use $ajax->form to work this fine for me.
Hope it help.
On May 7, 2:10 am, Robert McWay <[email protected]>
wrote:
> Hello All,
>
> I am having trouble with putting multiple ajax form instances on the
> same page. All the forms have the same fields, with the exception of a
> hidden field passing the User Id. Upon submitting the form, it always
> submits the form fields in the first form, regardless of which form i
> submit. I have given the each submit, and form unique ids, but it
> still seems to always submit that first form. Here is an example of a
> couple forms:
>
> <?php
> $update = 'availability'.$t['id'];
> $formid = 'a'.$t['id'];
> $submitid = 'submit'.$t['id'];
> ?>
> <?php echo $form->create('User', array('action'=>'check', 'id'=>
> $formid, 'name'=>$formid, 'id' => $submitid)); ?>
> <?php echo $form->hidden('tutor_id.'.$t['id'], array('value'=>
> $t['id']))?>
> ...more identical form checkbox fields
>
> <?php echo $ajax->submit('Check', array('url'=>
> array('controller'=>'users', 'action'=>'check'), 'update' => $update,
> 'id' => $submitid)); ?>
>
> Any ideas?
>
> Check out the new CakePHP Questions sitehttp://cakeqs.organd help others with
> their CakePHP related questions.
>
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Check out the new CakePHP Questions site http://cakeqs.org and help others with
their CakePHP related questions.
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