Use this
<?php
echo $html->script('jquery-1.3.2.min.js');
?>
---
Norman Paniagua
Desarrollo / WSDcamp
+ 595 981 184 430
www.webcamp.com
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2010/7/21 Velmurugan Kuberan <[email protected]>
> I create a default layout and added css and javascript into it like
> the following,
>
> For CSS I added the following lines in the head section of the
> default.ctp in layout folder
>
> echo $html->css('reset', 'stylesheet', array("media"=>"screen"))."\r
> \n ";
> echo $html->css('style', 'stylesheet', array("media"=>"screen"))."\r
> \n ";
> echo $html->css('invalid', 'stylesheet', array("media"=>"screen"))."\r
> \n\r\n ";
>
> It worked finely.
>
> Then I need to add javascript functionality
>
> So I added a line like this after the above code
>
> <!-- Javascripts -->
> <!-- jQuery -->
> <?php
> echo $javascript->link(array('jquery-1.3.2.min'));
> ?>
>
>
> I copy jquery-1.3.2.min to the default webroot/js folder (followed the
> cakephp convention)
>
> But I got a warning message like this:
>
> Notice (8): Undefined variable: javascript [APP\views\layouts
> \default.ctp, line 26]
> Fatal error: Call to a member function link() on a non-object in D:
> \xampp\htdocs\cakephp127\app\views\layouts\default.ctp on line 26
>
> I even use $javascript->includeScript() but again I got the same
> warning
>
> I can't able to use the javascript functionality,
>
> I am new to cakephp, so I want to know where I am making mistake.
>
> Check out the new CakePHP Questions site http://cakeqs.org and help others
> with their CakePHP related questions.
>
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>
Check out the new CakePHP Questions site http://cakeqs.org and help others with
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