Hi everyone,
I use a form to upload files and currently i do this with jquery to
simulate ajax, so if I want to pass the file data to my jquery
function I do this:
<div class="submit"><button onClick="refreshattachments(this.form)"
type="button">Upload</button></div>
But I want to switch to AJAX and I dont know how to pass the form data
within an ajax link:
echo $form->create('Links',
array('name'=>'uploadAttachmentsForm','id'=>'uploadAttachmentsForm','type'=>'file'));
echo $form->file('Links');
echo $ajax->link('Upload', '/links/processattachment'.this.form,
array('update' => 'attachments_content')
);
echo $form->end();
aware that "$ajax->link('Upload', '/links/
processattachment'.this.form," is far away from right I stil gave it a
shot.
Can someone help me? Thank you. I appreciate it.
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