Hi,
The column type is correct: tinyint(1)
I assumed that if the field is needed only to type tinyint declare the
label and the field, correct?
<? Php echo $ form-> input ('active', array ('label' => 'Active'))?>
user_group_id is a combo, it works fine.
The only checkbox is the 'active' field
Thanks!
On 23 sep, 14:04, MissYeh <[email protected]> wrote:
> 2 things:
>
> 1) Is the column type in the table set to boolean or tinyint(1)?
>
> 2) There is no array with the options passed in for your checkbox:
> echo $this->Form->input('field', array('options' => array('option1',
> 'option2')));
>
> If user_group_id is supposed to be the checkbox then the type is
> wrong, which then should be checkbox.
>
> Take a look at this
> example:http://book.cakephp.org/view/1390/Automagic-Form-Elements#options-mul...
>
> Hope this solves your issue, let us know! :)
>
> Kana
>
> On Sep 23, 12:26 pm, xamako <[email protected]> wrote:
>
> > Hi!
>
> > I have a problem with a checkbox.
>
> > I always get value 0.
>
> > My code is this:http://bin.cakephp.org/view/1438225730
>
> > Thanks
Check out the new CakePHP Questions site http://cakeqs.org and help others with
their CakePHP related questions.
You received this message because you are subscribed to the Google Groups
"CakePHP" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected] For more options, visit this group at
http://groups.google.com/group/cake-php?hl=en
