Hi,
You need to tell link() method to NOT escape the title, please have a look
at http://book.cakephp.org/view/1442/link for more help, though you can use
the following code as it is.
echo
$this->Html->link($this->Html->image('logout.png',array('alt'=>'logout')),array('controller'=>'users','action'=>'logout'),
*array('escape' => false)*);
Amit Badkas
PHP Applications for E-Biz: http://www.sanisoft.com
On Fri, Dec 31, 2010 at 3:05 PM, poor-grammar <[email protected]> wrote:
> echo $this->Html->link($this->Html-
> >image('logout.png',array('alt'=>'logout'))
>
> ,array('controller'=>'users','action'=>'logout'));
>
> $this->Html->image('logout.png',array('alt'=>'logout')--> this line is
> giving me html source
> <img src="/hr/img/logout.png" alt="logout" />..
> and i think it sould give me this html <img src="/hr/webroot/img/
> logout.png" alt="logout" />..
>
> am i missing any thing?
>
> Check out the new CakePHP Questions site http://cakeqs.org and help others
> with their CakePHP related questions.
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Check out the new CakePHP Questions site http://cakeqs.org and help others with
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