The classregistry way is the one I have seen as response to similar
questions.

In your example you are talking about races, so probably your Race
model has many cars and also has many spectators, in that case models
A and B are linked throug model C, so you could code something like:

$this->Car->Race->Spectator->find(....

Please cakephp gurus out there, correct me if I'm wrong.

Regards

On 21 feb, 09:48, Axel <[email protected]> wrote:
> Hello,
>
> I'm still a bit stuck in the MVC architecture. I've two models A and B
> which are not logically linked (let's imagine model A is a racing car
> and model B is a spectator of a race), so I haven't built any
> association between them. How can I use both models in a function in
> model A, I mean what is the best way to load B in A ? I4ve in mind two
> solution : first one is loading models in controller, retrieving data
> and passing them to function, but it's not controllers thin models
> fat. Second one is classregistry loading inside of the model, but
> might it be time consuming?
>
> Example :
>
> -------------FIRST example -------------------
> AController
> {
>
> function AAA($a_id,$b_id)
>  {
>  $a=$this->a->find(..conditions => ... a_id....)
>  $this->loadModel('b');
>  $b=$this->b->find((..conditions => ... b_id...);
>  $result=$this->a->funA($a,$b)
>  }
>
> }
>
> AModel
> {
> function funA($a,$b)
> {Logic, whole stuff, data treatment}
>
> }
>
> ------------SECOND example -----------------------
>
> AController
> {
> function AAA($a_id,$b_id)
>  {
>  $result=$this->a->funA($a_id,$b_id)
>  }
>
> }
>
> AModel
> {
> function funA($a_id,$b_id)
>  {
>  $a=$this->find(..conditions => ... a_id....)
>  $b=ClassRegistry::init(a)->find(..conditions => ... b_id....)
>  }
>
> }
>
> Thank you a lot!

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