On 03/01/2008, tog <[EMAIL PROTECTED]> wrote:
>
>
> >Today you have to do
> >
> >from("file://some/dir").beanRef("myBean");
> >from("file://some/other/file").beanRef("myBean");
>
> Will that fetch the 2 files before executing the bean or will that execute
> twice the same bean using as input each of the files ?

It will poll files in parallel from those directories/files and
process them in parallel. So the first route could generate 1000
messages to call the bean and the second could maybe generate one
message


> I suspect we need a kind of "join" somewhere here, isn't it ?
>
> Then how to express the second semantic ?

If you want to join the messages togeher into a single message; you
could either write your own Endpoint which knows how to relate the
file messages together - or you could use some kinda Aggregator
http://activemq.apache.org/camel/aggregator.html

-- 
James
-------
http://macstrac.blogspot.com/

Open Source Integration
http://open.iona.com

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