hi,
How can I transpose this splitter route (where there is no XPATH expression)
into XML ?
from("direct:A")
.splitter(body())
.to("bean:MyBean")
or
from("direct:A")
.splitter(body().tokenize(","))
.to("bean:MyBean")
It should be interesting to improve the documentation concerning this point.
Regards,
Charles Moulliard
-----
Enterprise Architect
Xpectis
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L-1470 Luxembourg
Phone +352 25 10 70 470
Mobile +352 621 45 36 22
e-mail : [EMAIL PROTECTED]
web site : www.xpectis.com
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