comp.lang.java.programmer
http://groups-beta.google.com/group/comp.lang.java.programmer
[EMAIL PROTECTED]

Today's topics:

* Scheduled Task in J2EE - 2 messages, 2 authors
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/a6228c0f82abecc8
* re. the Enumeration interface. - 3 messages, 3 authors
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/82c0021921f12557
* help with JDBC - 3 messages, 2 authors
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/a4767f119aa3583b
* Calling Overridden Methods without super - 1 messages, 1 author
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/b323ca46ffc0fc37
* Socket Programming - 1 messages, 1 author
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/47f5c36e2ad07276
* Is there a better parser (writen in java) than Jtidy? - 1 messages, 1 author
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/730b70675cf88346
* store whole InputStream in a String - 3 messages, 3 authors
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/d510835287103e9
* reuse HashMap$Entry (or HashMap in total) to avoid millions of allocations - 2 
messages, 2 authors
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/6d3d5d296d63ef30
* System.ext() - 7 messages, 4 authors
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/6008bc2e14d4e02e
* Java 1.5 to be released with nasty JEditorPane/HTML bug - 2 messages, 2 authors
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/18cd37410728e7bc
* Why this method behaves differently? - 1 messages, 1 author
  
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/f14afd9d997d1896
  
==========================================================================
TOPIC: Scheduled Task in J2EE
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/a6228c0f82abecc8
==========================================================================

== 1 of 2 ==
Date:   Sat,   Sep 11 2004 2:01 am
From: [EMAIL PROTECTED] (Ian Walsh) 

Hi,

I'm involved in a Java development project, and have to write an
application that runs every night. The infrastructure is Websphere
Server on a Regatta box.

If I was doing this in Windows using .Net I'd write a Windows Service.
What are the options in J2EE?

Any help appreciated. Thanks.



== 2 of 2 ==
Date:   Sat,   Sep 11 2004 8:53 am
From: [EMAIL PROTECTED] (Nathan Zumwalt) 

I'm not sure what a Regatta box is, but if it runs a Unix derivative,
you can create a cron job that makes a call to your Websphere app
server (EJB, webservices, etc) nightly.

Or, you could create a startup class that creates a thread that wakes
up every night.

Personally, I'd go for the cron job.

//Nathan

[EMAIL PROTECTED] (Ian Walsh) wrote in message news:<[EMAIL PROTECTED]>...
> Hi,
> 
> I'm involved in a Java development project, and have to write an
> application that runs every night. The infrastructure is Websphere
> Server on a Regatta box.
> 
> If I was doing this in Windows using .Net I'd write a Windows Service.
> What are the options in J2EE?
> 
> Any help appreciated. Thanks.




==========================================================================
TOPIC: re. the Enumeration interface.
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/82c0021921f12557
==========================================================================

== 1 of 3 ==
Date:   Sat,   Sep 11 2004 2:10 am
From: Michael Borgwardt <[EMAIL PROTECTED]> 

Steve R. Burrus wrote:
> Is the Enumeration interface archaic/deprecated by now??? If so, just 
> what are the proper methods that should be used now for whatever 
> replaced it some time ago???!!! I am trying to use Enumeration in a 
> particular servlet right now, but get compiler errors when it's 
> referenced in the servlet.

Even though it has been replaced by Iterators, Enumeration is not
officially deprecated and its usage as such should produce neither
compiler errors nor warnings.



== 2 of 3 ==
Date:   Sat,   Sep 11 2004 3:02 am
From: "Steve Cassidy" <[EMAIL PROTECTED]> 

"Steve R. Burrus" <[EMAIL PROTECTED]> wrote in message 
news:[EMAIL PROTECTED]
> Is the Enumeration interface archaic/deprecated by now??? If so, just
<>
> particular servlet right now, but get compiler errors when it's referenced 
> in the servlet.

The compiler may not be be able to find the Enumeration class. Try includng 
import java.util.Enumeration; or
import java.util.*; at the top you your class, or in the code try declaring 
the enumeration as java.util.Enumeration rather than just Enumeration. The 
import statement just lets you reference classes without putting their 
package names in front. If you look at the top of your servlet code, you'll 
probably see import javax.servlet.http.* - this is what's letting you 
reference HttpServletRequest etc in your doGet() declaration rather than 
having to type out javax.servlet.http.HttpServletRequest. That's what 
"import" is for. HTH.





== 3 of 3 ==
Date:   Sat,   Sep 11 2004 3:43 am
From: [EMAIL PROTECTED] 

"Steve R. Burrus" <[EMAIL PROTECTED]> wrote in message news:<[EMAIL PROTECTED]>...
> Is the Enumeration interface archaic/deprecated by now??? If so, just 
> what are the proper methods that should be used now for whatever 
> replaced it some time ago???!!! I am trying to use Enumeration in a 
> particular servlet right now, but get compiler errors when it's 
> referenced in the servlet.


I don't know why you're getting compiler errors; this certainly should
not happen due to an interface's deprecation (not that it has been).

Javadoc for Enumeration:
"NOTE: The functionality of this interface is duplicated by the
Iterator interface. In addition, Iterator adds an optional remove
operation, and has shorter method names. New implementations should
consider using Iterator in preference to Enumeration. "


.ed

www.EdmundKirwan.com - Home of The Fractal Class Composition




==========================================================================
TOPIC: help with JDBC
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/a4767f119aa3583b
==========================================================================

== 1 of 3 ==
Date:   Sat,   Sep 11 2004 3:01 am
From: [EMAIL PROTECTED] (Ebrahim) 

hi guys .. I am using Oracle : JDBC driver to connect to an oracle
server . I am reading the cols from the db into a ResultSet . When I
program in Eclipse I can read the values from rs.getString(col_name)(
the resultset object ) . But the same code does not work when I run my
code on my server - Tomcat .
It gives the Exception ResultSet.next() was not called . 
It does not make any sense ... coz it connects fine to the db fine but
does not read any values ...
BEsides why should ResultSet.Next() be called in the first place ??
(even though I do call it from my program ) Becoz I am reading only 1
row from the DB at a time so why call rs.next() .

S O M E  O N E  P L S  E X P L A I N ????????????????



== 2 of 3 ==
Date:   Sat,   Sep 11 2004 3:08 am
From: "Steve Cassidy" <[EMAIL PROTECTED]> 

"Ebrahim" <[EMAIL PROTECTED]> wrote in message 
news:[EMAIL PROTECTED]
> hi guys .. I am using Oracle : JDBC driver to connect to an oracle
> It gives the Exception ResultSet.next() was not called .
> BEsides why should ResultSet.Next() be called in the first place ??

rs.next() reads a row from the database into the ResultSet. When you first 
create a ResultSet with statement.executeQuery() or similar, the cursor into 
the ResultSet is initially positioned at the start, before the first row. 
Your first call to rs.next() reads the first row - you have to call it even 
if your query returns only one row. Until you've called this you can't 
retrieve any values, as there aren't any loaded to retrieve. 





== 3 of 3 ==
Date:   Sat,   Sep 11 2004 9:34 am
From: [EMAIL PROTECTED] (Ebrahim) 

"Steve Cassidy" <[EMAIL PROTECTED]> wrote in message news:<[EMAIL PROTECTED]>...
> "Ebrahim" <[EMAIL PROTECTED]> wrote in message 
> news:[EMAIL PROTECTED]
> > hi guys .. I am using Oracle : JDBC driver to connect to an oracle
> > It gives the Exception ResultSet.next() was not called .
> > BEsides why should ResultSet.Next() be called in the first place ??
> 
> rs.next() reads a row from the database into the ResultSet. When you first 
> create a ResultSet with statement.executeQuery() or similar, the cursor into 
> the ResultSet is initially positioned at the start, before the first row. 
> Your first call to rs.next() reads the first row - you have to call it even 
> if your query returns only one row. Until you've called this you can't 
> retrieve any values, as there aren't any loaded to retrieve.

 thx for clearing that doubt !!! 

could you also help me with the following :
i need to enter values into my Oracle db in chinese . For this I need
to set up the Oracle DB in chinese . Since I work for a company , they
might not allow me to change the charset for the entire database to
UTF-8 but rather only for a specific schema . Can you help me with
this ?? Do you know of any other way by which I can enter data in
Chinese/Japanese in an ORacle DB ??

Ebrahim B




==========================================================================
TOPIC: Calling Overridden Methods without super
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/b323ca46ffc0fc37
==========================================================================

== 1 of 1 ==
Date:   Sat,   Sep 11 2004 3:10 am
From: Joona I Palaste <[EMAIL PROTECTED]> 

Marco <[EMAIL PROTECTED]> scribbled the following:
> Can I call the overridden version of an object's foo() method 
> outside that object's class, without using super? EG:

> class MainProgram {
>   public static void main(String[] args) {
>     Beta b = new Beta();

>     // I want to invoke Alpha.foo() but on the Beta instance. 
>     // I want to cancel the dynamic binding that makes Beta.foo() 
>     // get called instead
>     // b.super.foo()        <---- obviously doesn't compile
>   }
> }

> class Alpha {
>   public void foo() { System.out.println("inside Alpha.foo()"); }
> }

> class Beta extends Alpha {
>   public void foo() { System.out.println("inside Beta.foo()"); }
> }

> Is this possible?
> Marco

No, and it shouldn't be. It is Beta's decision whether it wants to use
Alpha's foo() or its own, not the calling code's. Allowing code outside
the Beta class to influence the binding of its methods breaks the
concepts of polymorphism and encapsulation.
(If you absolutely insist, you might try using Reflection. Personally,
I find any use of Reflection a crude hack. I have never needed to use it
anywhere.)

-- 
/-- Joona Palaste ([EMAIL PROTECTED]) ------------- Finland --------\
\-- http://www.helsinki.fi/~palaste --------------------- rules! --------/
"Holy Banana of this, Sacred Coconut of that, Magic Axolotl of the other."
   - Guardian in "Jinxter"




==========================================================================
TOPIC: Socket Programming
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/47f5c36e2ad07276
==========================================================================

== 1 of 1 ==
Date:   Fri,   Sep 10 2004 9:06 pm
From: "Kathryn Bean" <[EMAIL PROTECTED]> 

In client/server application with Datagram, a client side sends a  message 
to a server and puts itself to sleep.  Can the client receive a replay from 
the server while sleeping or will the message be lost?

How about Stream Socket?

Thank you in advance.
Kathryn 






==========================================================================
TOPIC: Is there a better parser (writen in java) than Jtidy?
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/730b70675cf88346
==========================================================================

== 1 of 1 ==
Date:   Sat,   Sep 11 2004 5:35 am
From: "Ike" <[EMAIL PROTECTED]> 

you might want to give javacc a try. -Ike

"mike" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> regard:
>
>      i use Jtidy to translate HTML file into XHTML file,but Jtidy cannot
>      do good with complicated HTML files.
>
>      Is there a better parser to translate HTML files into XHTML files?
>
> thank you






==========================================================================
TOPIC: store whole InputStream in a String
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/d510835287103e9
==========================================================================

== 1 of 3 ==
Date:   Sat,   Sep 11 2004 5:37 am
From: "<- Chameleon ->" <[EMAIL PROTECTED]> 

Can I write all contents of an InputStream to a String at once?

something like

String a = inputStream.readAll();





== 2 of 3 ==
Date:   Sat,   Sep 11 2004 6:27 am
From: "ak" <[EMAIL PROTECTED]> 

> Can I write all contents of an InputStream to a String at once?
>
> something like
>
> String a = inputStream.readAll();
>
sure:

public String readAll(InputStream inputStream) {
    ByteArrayOutputStream bout = new ByteArrayOutputStream();
    byte [] buffer = new byte[1024];
    while(true) {
        int len = inputStream.read[buffer];
        if(len < 0) {
            break;
        }
        bout.write(buffer, 0, len);
    }
    byte [] data = bout.toByteArray();
    return new String(data);
}

String a = readAll(in);

-- 
Andrei Kouznetsov
http://uio.dev.java.net Unified I/O for Java
http://reader.imagero.com Java image reader





== 3 of 3 ==
Date:   Sat,   Sep 11 2004 8:36 am
From: Paul Lutus <[EMAIL PROTECTED]> 

ak wrote:

>> Can I write all contents of an InputStream to a String at once?
>>
>> something like
>>
>> String a = inputStream.readAll();
>>
> sure:
> 
> public String readAll(InputStream inputStream) {
>     ByteArrayOutputStream bout = new ByteArrayOutputStream();
>     byte [] buffer = new byte[1024];
>     while(true) {
>         int len = inputStream.read[buffer];
>         if(len < 0) {
>             break;
>         }
>         bout.write(buffer, 0, len);
>     }

??? Please consider the following, and avoid constructions like
"while(true)" and "break" when possible:

int len;

while((len = inputStream.read[buffer]) > 0) {
        bout.write(buffer, 0, len);
}

-- 
Paul Lutus
http://www.arachnoid.com





==========================================================================
TOPIC: reuse HashMap$Entry (or HashMap in total) to avoid millions of allocations
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/6d3d5d296d63ef30
==========================================================================

== 1 of 2 ==
Date:   Sat,   Sep 11 2004 6:51 am
From: Frank <[EMAIL PROTECTED]> 

Vince Darley wrote:
> Now, the problem with this is that the code spends 40%+ of its time
> allocating new HashMap$Entry objects (according the profiling we've
> done)

I'm sure you're reading your profiling data wrong.

Here's a dump from code which basically does nothing but add items to a 
hashmap. As you can see, HashMap$Entry.<init> doesn't show up until 
11th, at 1.67% CPU time.
Map.put() is bound to take some time, but perhaps you can shave off a 
few % by using a larger initial capacity.


CPU TIME (ms) BEGIN (total = 940616) Sat Sep 11 15:45:33 2004
rank   self  accum   count trace method
    1 32.60% 32.60%       1 301225 Q.main
    2 30.27% 62.87% 5300314 301127 java.util.HashMap.put
    3 11.31% 74.18% 5300314 301126 java.util.HashMap.addEntry
    4  5.43% 79.62% 5300314 301123 java.util.HashMap.hash
    5  5.40% 85.02%    1234 301130 java.util.HashMap.resize
    6  5.22% 90.24%    1234 301129 java.util.HashMap.transfer
    7  2.33% 92.57% 7262242 301128 java.util.HashMap.indexFor
    8  1.73% 94.30% 5300314 301124 java.util.HashMap.indexFor
    9  1.70% 95.99% 5300314 301122 java.lang.Integer.hashCode
   10  1.70% 97.69% 5300314 301121 java.util.HashMap.maskNull
   11  1.67% 99.36% 5300314 301125 java.util.HashMap$Entry.<init>
   12  0.10% 99.46%       2 301089 java.lang.Object.wait

>, and manages to allocate some 33 million of them (>1 Gb of
> memory in total), although certainly no more than 1/2 million are
> active at any one time (say 10-20Mb, according to the profiler).

The garbage collector may not be working too hard when there's plenty of 
free heap. Specify a heap size for the JVM if your program is laying 
claim on too much system resources.

-Frank



== 2 of 2 ==
Date:   Sat,   Sep 11 2004 8:37 am
From: "Jeff" <[EMAIL PROTECTED]> 

We had the same concern.

First, our analysis did not show the creation of entry as a big time
consumer.  Our profiling did not indicate it, nor did our discussions with
the JVM providers.  Object creation is reasonably fast.

Second, you could consider writing your own HashMap as another contributor
suggested.  java.util.HashMap uses an array for storage.  You could use
those methods as a starting point for your own class's methods.

"Vince Darley" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> An application we've built makes very extensive use of
> java.util.HashMaps to store the results of 10s of thousands of
> calculations it does.  Each of those calculations involves reading
> from/writing to a HashMap, eventually filling it with, say,
> 10000-100000 entries.  Once complete, the information is copied out
> into a fixed matrix, and we can safely discard the HashMap (and all
> its entries of course).
>
> Now, the problem with this is that the code spends 40%+ of its time
> allocating new HashMap$Entry objects (according the profiling we've
> done), and manages to allocate some 33 million of them (>1 Gb of
> memory in total), although certainly no more than 1/2 million are
> active at any one time (say 10-20Mb, according to the profiler).
>
> So, my question is: are there any suggestions for how we can
> restructure this code or its use of HashMap to avoid such a mad
> allocation/deallocation frenzy.  It would all, presumably, run more
> quickly if we could avoid this problem.
>
> Any ideas?
>
> Vince.






==========================================================================
TOPIC: System.ext()
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/6008bc2e14d4e02e
==========================================================================

== 1 of 7 ==
Date:   Sat,   Sep 11 2004 6:58 am
From: steph <[EMAIL PROTECTED]> 

Hello,

Is the any way to prevent a class to do a System.exit()

i.e: in my application, i invoque a gui with an 'exit' button and i don't want 
to stop the jvm when clicking on this button

thanks.
-- 
stephane
retirez les lettres majuscules et le 666 de l'adresse pour l'utiliser.
remove uppercase letters and 666 from email address to use.



== 2 of 7 ==
Date:   Sat,   Sep 11 2004 7:18 am
From: Mark Thornton <[EMAIL PROTECTED]> 

steph wrote:

> Hello,
> 
> Is the any way to prevent a class to do a System.exit()
> 
> i.e: in my application, i invoque a gui with an 'exit' button and i 
> don't want to stop the jvm when clicking on this button
> 
> thanks.

Install a SecurityManager (not always possible) and rejects attempts to 
call System.exit. The problem here is that you can't install a 
SecurityManager if one has already been installed.

Mark Thornton



== 3 of 7 ==
Date:   Sat,   Sep 11 2004 8:45 am
From: Andrew Thompson <[EMAIL PROTECTED]> 

On Sat, 11 Sep 2004 15:58:41 +0200, steph wrote:

> Is the any way to prevent a class to do a System.exit()

Yes.  Do not call System.exit() in your code.

> i.e: in my application, 

With or without a GUI?

> ..i invoque a gui with an 'exit' button 

Why would you invoke a GUI with a 
button labelled 'exit'?

>..and i don't want 
> to stop the jvm when clicking on this button

So don't.

(To get more meaningful answers, you 
are going to need to make more sense)

-- 
Andrew Thompson
http://www.PhySci.org/ Open-source software suite
http://www.PhySci.org/codes/ Web & IT Help
http://www.1point1C.org/ Science & Technology



== 4 of 7 ==
Date:   Sat,   Sep 11 2004 8:54 am
From: Mark Thornton <[EMAIL PROTECTED]> 

Andrew Thompson wrote:

> On Sat, 11 Sep 2004 15:58:41 +0200, steph wrote:
> 
> 
>>Is the any way to prevent a class to do a System.exit()
> 
> 
> Yes.  Do not call System.exit() in your code.
> 
> 
>>i.e: in my application, 
> 
> 
> With or without a GUI?
> 
> 
>>..i invoque a gui with an 'exit' button 
> 
> 
> Why would you invoke a GUI with a 
> button labelled 'exit'?
> 
> 
>>..and i don't want 
>>to stop the jvm when clicking on this button
> 
> 
> So don't.
> 
> (To get more meaningful answers, you 
> are going to need to make more sense)
> 

I presume that he is calling some gui code that he didn't write or 
doesn't have permission to modify. That gui code has an exit button 
which invokes System.exit. He wants to be able to stop that gui code 
from terminating the VM.
Its a nasty problem which arose originally from the need for any GUI 
code to use System.exit if the application was ever to exit. This is no 
longer necessary as the gui threads will now terminate once there are no 
active frames. However there is still a lot of code which still uses 
System.exit.
It is easy to make sense of this request if you recognise the symptoms 
of the dilemma.

Mark Thornton



== 5 of 7 ==
Date:   Sat,   Sep 11 2004 9:22 am
From: Andrew Thompson <[EMAIL PROTECTED]> 

On Sat, 11 Sep 2004 16:54:12 +0100, Mark Thornton wrote:

> It is easy to make sense of this request if you recognise the symptoms 
> of the dilemma.

Or if it's put the way you put it.

-- 
Andrew Thompson
http://www.PhySci.org/ Open-source software suite
http://www.PhySci.org/codes/ Web & IT Help
http://www.1point1C.org/ Science & Technology



== 6 of 7 ==
Date:   Sat,   Sep 11 2004 9:24 am
From: Andrew Thompson <[EMAIL PROTECTED]> 

On Sat, 11 Sep 2004 15:18:04 +0100, Mark Thornton wrote:

> steph wrote:
..
>> Is the any way to prevent a class to do a System.exit()
..
> Install a SecurityManager (not always possible) and rejects attempts to 
> call System.exit. The problem here is that you can't install a 
> SecurityManager if one has already been installed.

Can't you install a more retricted security
manager?  I thought it was simply that you 
could not install a new security manager with
more/wider permissions than the parent.

-- 
Andrew Thompson
http://www.PhySci.org/ Open-source software suite
http://www.PhySci.org/codes/ Web & IT Help
http://www.1point1C.org/ Science & Technology



== 7 of 7 ==
Date:   Sat,   Sep 11 2004 9:42 am
From: Sudsy <[EMAIL PROTECTED]> 

Andrew Thompson wrote:
> On Sat, 11 Sep 2004 15:18:04 +0100, Mark Thornton wrote:
> 
> 
>>steph wrote:
> 
> ..
> 
>>>Is the any way to prevent a class to do a System.exit()
>>
> ..
> 
>>Install a SecurityManager (not always possible) and rejects attempts to 
>>call System.exit. The problem here is that you can't install a 
>>SecurityManager if one has already been installed.
> 
> 
> Can't you install a more retricted security
> manager?  I thought it was simply that you 
> could not install a new security manager with
> more/wider permissions than the parent.
> 

 From the javadocs for System#setSecurityManager:

"If there is a security manager already installed, this method first
calls the security manager's checkPermission method with a
RuntimePermission("setSecurityManager")  permission to ensure it's ok
to replace the existing security manager. This may result in throwing
a SecurityException."

So a security manager can only be replaced if it allows itself to
be replaced.





==========================================================================
TOPIC: Java 1.5 to be released with nasty JEditorPane/HTML bug
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/18cd37410728e7bc
==========================================================================

== 1 of 2 ==
Date:   Sat,   Sep 11 2004 7:17 am
From: Tor Iver Wilhelmsen <[EMAIL PROTECTED]> 

"Larry Barowski" <larrybarATengDOTauburnDOTeduANDthatISall> writes:

> I would suggest voting for this bug, but it is marked as "Closed,
> fixed" - in "mustang", which I guess is 1.6.

I would rather guess 1.5.1; 1.6 is at least 18 months away using the
"standard" release schedule.



== 2 of 2 ==
Date:   Sat,   Sep 11 2004 7:16 am
From: Mark Thornton <[EMAIL PROTECTED]> 

Tor Iver Wilhelmsen wrote:
> "Larry Barowski" <larrybarATengDOTauburnDOTeduANDthatISall> writes:
> 
> 
>>I would suggest voting for this bug, but it is marked as "Closed,
>>fixed" - in "mustang", which I guess is 1.6.
> 
> 
> I would rather guess 1.5.1; 1.6 is at least 18 months away using the
> "standard" release schedule.

Unfortunately Mustang is indeed 1.6 (or 6.0 now). I don't know if a code 
name has been allocated for (1.)5.1. Important fixes currently labeled 
as Mustang may be migrated to what ever they choose to call 5.1.

Mark Thornton




==========================================================================
TOPIC: Why this method behaves differently?
http://groups-beta.google.com/group/comp.lang.java.programmer/browse_thread/thread/f14afd9d997d1896
==========================================================================

== 1 of 1 ==
Date:   Sat,   Sep 11 2004 8:30 am
From: [EMAIL PROTECTED] (otsarri) 

I think I got it! At least I know now what's going on. I'll try both
of the solutions and see which one suits me best.

Many thanks,
Otsarri



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