hiii,
Usin' for loop i've already sent a program to print diamond.now i've tried to make it with recursion.
guys i'm sendin' a solution to saud's prob with recursion in two ways.
first one is with while loop .
function is recursive after printin' one line.
*************************************************************
#include<stdio.h>
#include<conio.h>
void diamond(int, int, int);
void main()
{
int n;
clrscr();
printf("Input a number");
scanf("%d",&n);
diamond (1,1,n);
getch();
}
void diamond(int i, int j, int n)
{
if(i<=n)
{
while(j<=i)
{
printf("*");
j++;
}
printf("\n");
return diamond(i+1,1,n);
}
if(n-1>=1)
{
while(j<=i-n)
{
printf(" ");
j++;
}
j=1;
while(j<=n-1)
{
printf("*");
j++;
}
printf("\n");
return diamond(i,1,n-1);
}
else
return;
}
****************************************************
in this program i've tries not to use even a single while loop.
function is recursive after printin' each * and even space.
if any can make this program in a better way please mail it in the group
#include<stdio.h>
#include<conio.h>
void diamond(int, int, int,int);
void main()
{
int n;
clrscr();
printf("Input a number");
scanf("%d",&n);
diamond (1,1,n,1);
getch();
}
void diamond(int i, int j, int n,int k)
{
if(i<=n)
{
if(j<=i)
{
printf("*");
diamond(i,j+1,n,k);
}
else
{
printf("\n");
diamond(i+1,1,n,k);
}
}
if(n-1>=1 && k==1)
{
if(j<=i-n )
{
printf(" ");
diamond(i,j+1,n,1);
}
else
diamond(i,1,n,0);
}
if(n-1>=1 && k==0)
{
if(j<=n-1 )
{
printf("*");
diamond(i,j+1,n,0);
}
else
{
printf("\n");
diamond(i,1,n-1,1);
}
}
getch();
exit();
}
***************************************************************************
thx
girish
saud aziz <[EMAIL PROTECTED]> wrote:
Can anyone tell me using for loop as well as (if possible) with
recursion how would i make a program that creates diamond like this:
1 *
2 *
**
*
3 *
**
***
**
*
for a function that takes in # of lines, so the last diamond above
should be displayed if user enters 3.
--
"Our lives begin to end the day we become silent about things that
matter." Dr. Martin Luther King Jr.
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