Mark Van Peteghem <[EMAIL PROTECTED]> wrote:
> The purpose of this is that you can use more than assignment at a
>time,
> just like with primitive types:
>
> form1 a, b, c;
> a = b = c;
>
> Remember that operator= is always evaluated from right to left, so
>it's
> equivalent to a = (b = c), so first b = c is done. This returns a
> reference to b, if the implementation ends with return *this. Then a
>= b
> is done.
> If you don't return a reference, like in form1, it probably would
>work
> as well, but slower, because then a copy is returned every time.
>
> --
> Mark Van Peteghem
> http://www.q-mentum.com -- easier and more powerful unit testing
hiii,
template <class _tipe>
class Item
{
public:
Item() {
mpData = NULL;
}
Item &operator=(const _tipe &rNewData) { //FIXME!!!
setData(rNewData);
return *this;
}
void setData(const _tipe &rNewData) {
if (mpData != NULL)
delete mpData;
mpData = new _tipe(rNewData);
}
_tipe getData() const {
return (*mpData);
}
virtual ~Item() {
if (mpData != NULL)
delete mpData;
}
private:
_tipe *mpData;
};
int main()
{
Item<int> a;
a = 4;
cout << a.getData() << endl;
return 0;
}
the code above will output: 4
but when i not use reference on operator=, the result will be 0
why does this happen?
is that my code above safe(especially memory leak)
could i assign int value for 'a object' repeatedly, for instance
a = 5;
a = 6; //and etc, will it be memory leak
thanx and regards
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