If it were me, I'd define each server in two roles, :server, and then
either :even or :odd.
%w(test01 test02 test03 test04).each_with_index do |host, index|
which = (index+1) % 2 == 0 ? :even : :odd
server(host, :server, which)
end
task :stop_odd, :roles => :odd do
# ...
end
Alternatively, if you're masochistic ;) you can specify a proc as the
value of the :hosts key, and return the servers you want that way.
Something like this:
%w(test01 test02 test03 test04).each_with_index do |host, index|
role :server, host, :machine => index+1
end
select_odd_hosts = Proc.new do
find_servers(:roles => :server).select { |s| s.options[:machine]
% 2 == 1 }
end
task :stop_odd, :hosts => select_odd_hosts do
# ...
end
- Jamis
On May 2, 2008, at 2:00 PM, alpduhuez wrote:
>
> Hello...
> I'm new to Capistrano, love it so far, great tool. I am trying to
> have more than one condition to select a task. I have lots of servers
> and would like to deploy to them in groups of odd/even. Here is what
> I am trying to do, is this possible with some syntax?
>
> I have a server defined as:
> role :server, "test01", :machine => 1
> role :server, "test02", :machine => 2
> role :server, "test03", :machine => 3
>
> task :stop_odd, :roles => :server, :only => { :machine =>
> 1, :machine => 3 , :machine => 5 } do
> run "echo Hello, $HOSTNAME"
> end
>
> This way only the last entry is used. I also tried:
>
> task :stop_odd, :roles => :server, :only => { :machine => 1
> || :machine => 3 || :machine => 5 } do
> run "echo Hello, $HOSTNAME"
> end
>
> I also tried expressions but that didn't work either. Is there some
> way to do this?
>
> Thanks!
> >
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