can anyone help with this?

thanks

On Friday, January 26, 2018 at 9:28:20 AM UTC-8, satnam wrote:
>
> Hello
>
> In 5.2, objectGUID (octelstring) get returned as  ?d? e??C? zx?cj   
> i am not sure what format is this and how to convert this to 
> uniqueidentifier string. In 4.2, GUID get return in readable format.  
>
> Do I have to covert this value myself or there is setting to get value in 
> correct format?
>
> my LDAP setting are
>
> cas.authn.ldap[0].type=AUTHENTICATED
> cas.authn.ldap[0].ldapUrl= ** URL
> cas.authn.ldap[0].useSsl=false
> cas.authn.ldap[0].baseDn=OU=XX,OU=__XX,dc=capost,dc=local
>
> cas.authn.ldap[0].userFilter=(|(sAMAccountName={user})(proxyAddresses=smtp:{user}))
> cas.authn.ldap[0].bindDn=CN=XX,OU=XX,OU=XXX,OU=__XX,DC=capost,DC=local
> cas.authn.ldap[0].bindCredential=XXXXX
> cas.authn.ldap[0].principalAttributeId=objectGUID
>
> cas.authn.ldap[0].principalAttributeList=sn,cn:commonName,givenName,objectGUID,msExchBlockedSendersHash,msExchMailboxGuid
> cas.authn.ldap[0].connectTimeout=5000
> cas.authn.ldap[0].subtreeSearch=true
> cas.authn.ldap[0].order=5
> #cas.authn.ldap[0].principal=objectGUID
> cas.authn.ldap[0].enhanceWithEntryResolver=true
>
>

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