Hi Jerome,
I get your direction. But still some holes I find hard to understand.
1. I had to modify auditTrailContext.xml (and not the reference bean at
the deployConfigContext):
<!-- List<AuditTrailManager> auditTrailManagers -->
<constructor-arg index="2">
<list>
<bean
class="com.github.inspektr.audit.support.ConsoleAuditTrailManager" />
<bean class="org.jasig.cas.audit.MyAuditTrailManager" />
<ref local="auditManager" />
</list>
</constructor-arg>
Hope that make sense?
2. After I injected the ServicesManager and extract the service name (via
the service ip) I want to log it to the current com_audit_trail and not
creating new table just for that.
3. Any idea how to integrate this within the current auditing mechanism
? I created new column serviceName. But how I actually log that name together
with current auditing data
Thanks.
From: Jérôme LELEU [mailto:[email protected]]
Sent: Thursday, May 15, 2014 2:25 PM
To: [email protected]
Subject: Re: [cas-user] Determine Service name via Audit trail
Hi,
1) In the deployerConfigContext.xml, you reference an audit trail class:
https://github.com/Jasig/cas/blob/master/cas-server-webapp/src/main/webapp/WEB-INF/deployerConfigContext.xml#L180.
You would need to create your own.
2) Programmatically yes by using the ServicesManager class injected in your new
MyAuditTrailManager.
Best regards,
Jérôme
2014-05-15 13:17 GMT+02:00 Idan Fridman
<[email protected]<mailto:[email protected]>>:
Hi Jerome,
1. Which Audit class?
2. How do you query the services manager? Programmatically?
From: Jérôme LELEU [mailto:[email protected]<mailto:[email protected]>]
Sent: Thursday, May 15, 2014 2:16 PM
To: [email protected]<mailto:[email protected]>
Subject: Re: [cas-user] Determine Service name via Audit trail
Hi,
I think you just have the service url in the audit class. So you would need to
query the services manager with this service url to get the matching service to
finally get its name.
Best regards,
Jérôme
2014-05-15 10:10 GMT+02:00 ray
<[email protected]<mailto:[email protected]>>:
Wonder if anyone had a chance to have any idea at this one?
Thanks,
ray.
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