Kelley,
You've most likely modified the CAS server's casLoginView.jsp and specified
an action in the form view that does not include the service parameter.
-Scott
On 2/9/07, Kelley Trombly-Freytag <[EMAIL PROTECTED]> wrote:
Our problem is that after the setup described below, we go to the
casLoginGenericSuccess view instead of back to our application.
I have recently downloaded CAS Server 3.0.6 Final and the JA-SIG CAS Java
Client
3.0.
We have verified that the CAS server installation on tomcat 5.0.30 works
out of
the box.
We have created a mindless web application (that works). We then put the
filter definitions per the current "JA-SIG CAS Client for Java", page;
created
the WEB-INF/securityConfiguration.xml and WEB-INF/cas-client.propertiesfiles.
These were customized as follows:
server.xml - we changed the CAS Validation Filter to be /*
securityConfiguration.xm:
-for ticketValidator we got startup errors stating it could not
find
a constructor to match our arguements (tomcat log). In checking
out
the source, we noted there were 6 arguments in the example from
the
web page, and either 5 or 8 in the most recent version of the
source.
We went with the 5 argument constructor: using the properties for
casServerUrl and renew, leaving the example along for HttpClient,
proxyChains (which was null) and acceptAnyProxy (true).
-for the casValidationFilter argument #1, we gave the
URL of our application as follows serverName:8080/castest
-for the casAuthenticationFilter argument #1, we gave the same URL
as for casValidationFilter
cas-client.properties:
-we changed all references to localhost:8443 to serverName:8443
Invoking our web application correctly sends us to CAS to authenticate,
which
we do. Then, as stated above, we get the casLoginGenericSuccess view,
instead of
being redirected.
Can someone give us advice on what we are doing wrong?
Kelley Trombly-Freytag
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http://tp.its.yale.edu/mailman/listinfo/cas
