Hi John,
Quickly spiked this as a solution, and it appears this does not
acheive the desired solution (unless my spike is wrong of course).
Here's the spike:
[TestFixture]
public class ContainerSpike
{
[Test]
public void EachAggregateInstanceShouldBeCreatedWithNewDependency
()
{
var container = new WindsorContainer();
container.Register(
Component.For<MyService>(),
Component.For<Child>().LifeStyle.Transient,
Component.For<MyController>().LifeStyle.Transient);
var c1 = container.Resolve<MyController>();
var c2 = container.Resolve<MyController>();
Assert.That(c1.Dependency, Is.SameAs(c1.MyChild.Dependency));
Assert.That(c2.Dependency, Is.SameAs(c2.MyChild.Dependency));
//This fails - both MyController incorrectly share the same
instance of MySerive
Assert.That(c1.Dependency, Is.Not.SameAs(c2.Dependency));
}
public class MyController {
public MyController(MyService dependency, Child child) {
Dependency = dependency;
MyChild = child;
}
public MyService Dependency { get; set; }
public Child MyChild { get; set; }
}
public class Child {
public Child(MyService dependency) {
Dependency = dependency;
}
public MyService Dependency { get; set; }
}
public class MyService { }
}
On 23 Feb, 20:58, jsimons <[email protected]> wrote:
> Hi Christian,
>
> Why do you need a lifestyle?
> Why not register MyController as transient and Dependencies as
> singleton.
>
> Cheers
> John
>
> On Feb 24, 7:12 am, christianacca <[email protected]>
> wrote:
>
> > I would like to define a lifestyle (?) that allows me to do the
> > following
>
> > var c1 = IoC.Resolve<MyController>();
> > var c2 = IoC.Resolve<MyController>();
>
> > Assert.IsTrue(ReferenceEquals(c1.Dependency, c1.Child.Dependency));
> > Assert.IsTrue(ReferenceEquals(c2.Dependency, c2.Child.Dependency));
> > Assert.IsFalse(ReferenceEquals(c1.Dependency, c2.Dependency));
>
> > In other words, each instance of MyController should be injected with
> > a new instance of Dependency; that each object within the MyController
> > share the same instance of Dependency.
>
> > Any ideas and how this could be acheived (I am expecting the answer
> > will be create a custom ILifestyleManager - in that case I'm looking
> > for some ideas of what the implementation would look like).
>
> > Thanks in advance
> > Christian
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