What I mean is that you'll get List<object[]> probably. As you have projections, each indice of the array that represents one row in database will correspond to one property result[0]=>row result[0][0]=>First name for the first row.
If you need something that is not array, you should use result transformers, i don't remember the name though. Tuna Toksöz Eternal sunshine of the open source mind. http://devlicio.us/blogs/tuna_toksoz http://tunatoksoz.com http://twitter.com/tehlike On Tue, Sep 8, 2009 at 9:38 PM, Tuna Toksoz <[email protected]> wrote: > The result is an array of an array.What you see is pretty normal. > Try to debug, you'll see. You need to use a sort of DTO + Result > Transformer. > > isreadonly,isfixedsize,longlength,rank etc... > > sounds more like Props of an array, doesn't it? > > Tuna Toksöz > Eternal sunshine of the open source mind. > > http://devlicio.us/blogs/tuna_toksoz > http://tunatoksoz.com > http://twitter.com/tehlike > > > > > On Tue, Sep 8, 2009 at 9:18 PM, olcay şeker <[email protected]> wrote: > >> >> i have already use it. please check sample app and you will see the >> result or my fault... >> >> On 9 Eylül, 04:01, Ayende Rahien <[email protected]> wrote: >> > Projections.ProjectionList() >> > >> > >> > >> > On Tue, Sep 8, 2009 at 5:22 AM, olcay şeker <[email protected]> >> wrote: >> > >> > > how can i write this query "select firstname,lastname from employees >> > > " with ICriteria api instead of hql? i tried with projection but >> > > failed. >> > >> > > session.CreateCriteria(typeof(employees)).SetProjection >> > > (Projections.Property("firstname")).SetProjection(Projections.Property >> > > ("lastname")).List(); >> >> >> > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Castle Project Users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/castle-project-users?hl=en -~----------~----~----~----~------~----~------~--~---
