Hi,

I need some help in understanding this issue. I'm using the repository
pattern with ActiveRecordMediator. I've enabled the session scope http
module, marked my classes with the ActiveRecord(Lazy = true).

The problem is that each time I perform a FindAll or SlicedFindAll,
the mediator returns a collection of initialized elements instead of
proxies. Could someone point me out in the right direction?

This is my repository:

public interface IEntityRepository<TEntity>
{
       IList<TEntity> FindAll(int page, int pageSize, out int
resultCount);
}

public class EntityRepository<TEntity> : IEntityRepository<TEntity>{
       public virtual IList<TEntity> FindAll(int page, int pageSize)
       {
            return
(IList<TEntity>)ActiveRecordMediator.SlicedFindAll(typeof(TEntity),
(page * pageSize), pageSize);
       }
}

[ActiveRecord(Lazy = true)]
public class DocumentEntity
{
        private Guid _id;
        private IList<DocumentVersionEntity> _versions;

        [PrimaryKey(PrimaryKeyType.GuidComb, "Id")]
        public virtual Guid Id
        {
            get { return _id; }
            set { _id = value; }
        }

        [HasAndBelongsToMany(typeof(DocumentVersionEntity),
RelationType.Bag, Table = DocumentEntriesToDocumentVersions",
ColumnKey = "DocumentEntryId",
                             ColumnRef = "DocumentVersionId", Cascade
= ManyRelationCascadeEnum.AllDeleteOrphan, Lazy = true)]
        public virtual IList<DocumentVersionEntity> Versions
        {
            get { return _versions; }
            set { _versions = value; }
        }
}

[ActiveRecord(Lazy = true)]
public class DocumentVersionEntity
{
        private Guid _id;

        [PrimaryKey(PrimaryKeyType.GuidComb, "Id")]
        public virtual Guid Id
        {
            get { return _id; }
            set { _id = value; }
        }
}

When I execute the FindAll method, all the objects in the Versions
array of the DocumentEntity are DocumentVersionEntity instead of
DocumentVersionEntityProxy and are all intialized.

What am I doing wrong?

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