You may want a <HasMany()> on the other ends of the <Any()> relationships.
You need to specify the foreign key column, AR/NH will infer the rest from
the list type.

-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of paulddw
Sent: 09 April 2011 03:26 PM
To: Castle Project Users
Subject: Opposite side of an "Any"

I have a class that looks like this

public class Comment
{
[Any(typeof(int), MetaType=typeof(int),
    TypeColumn="RecordTypeID",
    IdColumn="RecordID",
    Cascade=CascadeEnum.SaveUpdate)]
[Any.MetaValue(1, typeof(News))]
[Any.MetaValue(2, typeof(Feature))]
public IContentItem Item
{get;set;}
}
How do I Create the Many on the News/Feature side??

public class News : IContentItem
{
[ManyRelationship]
public IList<Comment> Comments
{get;set;}
}

public class Feature : IContentItem
{
[ManyRelationship]
public IList<Comment> Comments
{get;set;}
}
Anyone got any ideas on this please I have been mucking around with this for
a few days. By the way the answer is not HasManyToAny

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