Anna,
Just get the base type and call the #enumerate method.
XMLType base = complexType.getBaseType().
if (XMLType.isComplexType()) {
ComplexType ctBase = (ComplexType);
Enumeration enum = ctBase.enumerate();
while (enum.hasMoreElements()) {
Structure struct = (Structure) enum.nextElement();
...
}
}
--Keith
> Anna Afonchenko wrote:
>
> Is there a way to get the elements defined in the extension of the
> complexContent for a complexType element?
> E.g., given following schema snippet if I have ElementDecl holding the
> div element, can I get the extension elements?
> I can't find anything like this in the API.
>
> <xs:element name="div">
>
> <xs:annotation>
>
> <xs:documentation>
>
> generic language/style container
>
> </xs:documentation>
>
> </xs:annotation>
>
> <xs:complexType mixed="true">
>
> <xs:complexContent mixed="true">
>
> <xs:extension base="Flow">
>
> <xs:attributeGroup ref="attrs"/>
>
> </xs:extension>
>
> </xs:complexContent>
>
> </xs:complexType>
>
> </xs:element>
>
> Thank you very much for help.
>
> Anna
>
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