In this task, we are told that "R1 should prefer routes to BB3s
loopbacks with an odd 4th octet via Cat1 and with an even octet via
Cat2."
The routes are from 192.168.3.15 through 192.168.3.34
R1#sir rip | in 192.168.3.
192.168.3.0/32 is subnetted, 21 subnets
R 192.168.3.34 [120/4] via 143.43.102.36, 00:00:11,
FastEthernet0/1
R 192.168.3.33 [120/4] via 143.43.101.35, 00:00:26,
FastEthernet0/0
R 192.168.3.32 [120/4] via 143.43.102.36, 00:00:11,
FastEthernet0/1
R 192.168.3.15 [120/4] via 143.43.101.35, 00:00:26,
FastEthernet0/0
R 192.168.3.14 [120/4] via 143.43.102.36, 00:00:11,
FastEthernet0/1
R 192.168.3.27 [120/4] via 143.43.101.35, 00:00:26,
FastEthernet0/0
R 192.168.3.26 [120/4] via 143.43.102.36, 00:00:11,
FastEthernet0/1
R 192.168.3.25 [120/4] via 143.43.101.35, 00:00:26,
FastEthernet0/0
R 192.168.3.24 [120/4] via 143.43.102.36, 00:00:11,
FastEthernet0/1
R 192.168.3.31 [120/4] via 143.43.101.35, 00:00:26,
FastEthernet0/0
R 192.168.3.30 [120/4] via 143.43.102.36, 00:00:11,
FastEthernet0/1
R 192.168.3.29 [120/4] via 143.43.101.35, 00:00:26,
FastEthernet0/0
R 192.168.3.28 [120/4] via 143.43.102.36, 00:00:11,
FastEthernet0/1
R 192.168.3.19 [120/4] via 143.43.101.35, 00:00:27,
FastEthernet0/0
R 192.168.3.18 [120/4] via 143.43.102.36, 00:00:12,
FastEthernet0/1
R 192.168.3.17 [120/4] via 143.43.101.35, 00:00:27,
FastEthernet0/0
R 192.168.3.16 [120/4] via 143.43.102.36, 00:00:12,
FastEthernet0/1
R 192.168.3.23 [120/4] via 143.43.101.35, 00:00:27,
FastEthernet0/0
R 192.168.3.22 [120/4] via 143.43.102.36, 00:00:12,
FastEthernet0/1
R 192.168.3.21 [120/4] via 143.43.101.35, 00:00:27,
FastEthernet0/0
R 192.168.3.20 [120/4] via 143.43.102.36, 00:00:12,
FastEthernet0/1
I used the following ACL:
access-list 1 remark odd nets
access-list 1 permit 192.168.3.15
access-list 1 permit 192.168.3.17 0.0.0.14
access-list 1 permit 192.168.3.33
access-list 2 remark even nets
access-list 2 permit 192.168.3.16 0.0.0.14
access-list 2 permit 192.168.3.32 0.0.0.2
The PG used the following:
access-list 41 permit 192.168.3.1 0.0.0.62
access-list 42 permt 192.168.3.0 0.0.0.62
Wouldn't the PG solution be over-summarizing and therefore considered
wrong, or am I missing something?
Thanks,
Rich
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