128 64 32 16 8 4 2 1 So in binary, 64 is 01000000 and 65 is 01000001
Where is the last bit that these two are the same? 64 = 0100000|0 65 = 0100000|1 that's only 1 bit of difference or 7 bits, so that's how you get the CIDR notation of /7, and /7 is a supernet encompassing 64.0.0.0 through 65.255.255.254 Thank you, Steve Di Bias Network Engineer - Information Systems Valley Health System - Las Vegas Office - 702- 369-7594 Cell - 702-241-1801 [email protected] -----Original Message----- From: [email protected] [mailto:[email protected]] On Behalf Of Lemish, Christopher Sent: Wednesday, January 26, 2011 12:42 PM To: [email protected] Subject: [OSL | CCIE_RS] Lab 8.15 - Binary logic Could someone explain the 64.0.0.0/7 binary logic that leads you to 64.0.0.0 and 65.0.0.0? I understand that /7 is 254.0.0.0 Thank you, Chris This email and any files transmitted with it are confidential and are intended for the sole use of the individual(s) to whom they are properly addressed. Any use, dissemination or forwarding of this email and any files transmitted with it by anyone other than the intended recipient(s) is strictly prohibited. If you have received this email in error, please notify the sender by replying to this email. Black Box Corporation and its affiliates reserve the right to scan and monitor all e-mail traffic. _______________________________________________ For more information regarding industry leading CCIE Lab training, please visit www.ipexpert.com UHS Confidentiality Notice: This e-mail message, including any attachments, is for the sole use of the intended recipient (s) and may contain confidential and privileged information. Any unauthorized review, use, disclosure or distribution of this information is prohibited. If this was sent to you in error, please notify the sender by reply e-mail and destroy all copies of the original message. _______________________________________________ For more information regarding industry leading CCIE Lab training, please visit www.ipexpert.com
