Hi Fulvio,

I think your confusion comes from the usual split-horizon definition
that "a route is never advertised out an interface it is learned
from," but that's an incomplete definition. Split-horizon comes into
play when the *best* route is learned from an interface, in which case
it will not be sent back out that same interface. Since R1 & R2 in
your example would each have their best path (successor route) through
their "other" interface, they would both advertise a path onto the
common segment for R1-4. R3 & R4 would learn equal-cost routes via
both 1 & 2.

Hope that helps,
Bob

Sent from my iPad

On Aug 9, 2012, at 10:55 AM, Fulvio allegretti <[email protected]> wrote:

> Right, I know the best thing to do here would be to lab this and I will, 
> promise, but I'd like to know your understanding on this and if it is 
> something to worry about.
> Let's say we have 4 routers on a LAN all talking eigrp. Two of these routers, 
> router 1 and 2, have an eigrp path to subnet 1.1.1.0/24 somewhere else  
> thorugh an interface  not on the LAN and lets's assume for sake of argument 
> that the metric to 1.1.1.0/24 is the same for both of them. Considering 
> split-horizon there will be only one router, 1 or 2, injecting that route on 
> the LAN, right? One of the two routers will have its best path to 1.1.1.0/24 
> through its own interface but won't inject it on the lan as it heard it  
> injected on the LAN from the other one.
> 1) What decides which one of the two will inject the route on LAN? Is it the 
> first router timewise that injects it on the LAN?
> 2) Let's assume R1 did, what happens if the metric through R2 "improves", 
> would the LAN routers choose the path through R2 now?
> Fulvio
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