So 64 byte packets account for 31.3% of traffic 96 byte 25.4%
128 byte 6.8% 160 byte 15.9% And so on If you add those percentages up you get about 99.7%. So the other .003 percent are mixed in with the rest. Regards, Tyson Scott - CCIE #13513 R&S, Security, and SP Managing Partner / Sr. Instructor - IPexpert, Inc. Mailto: [email protected] Telephone: +1.810.326.1444, ext. 208 Live Assistance, Please visit: www.ipexpert.com/chat eFax: +1.810.454.0130 IPexpert is a premier provider of Self-Study Workbooks, Video on Demand, Audio Tools, Online Hardware Rental and Classroom Training for the Cisco CCIE (R&S, Voice, Security & Service Provider) certification(s) with training locations throughout the United States, Europe, South Asia and Australia. Be sure to visit our online communities at www.ipexpert.com/communities and our public website at www.ipexpert.com <http://www.ipexpert.com/> From: [email protected] [mailto:[email protected]] On Behalf Of Kingsley Charles Sent: Monday, July 12, 2010 7:44 AM To: [email protected] Subject: [OSL | CCIE_Security] sh ip cache verbose flow Hi all I am trying to interpret the following: router#sh ip cache verbose flow IP packet size distribution (95662 total packets): 1-32 64 96 128 160 192 224 256 288 320 352 384 416 448 480 .000 .313 .254 .068 .159 .079 .063 .061 .000 .000 .000 .000 .000 .000 .000 512 544 576 1024 1536 2048 2560 3072 3584 4096 4608 .000 .000 .000 .000 .000 .000 .000 .000 .000 .000 .000 The packet size distribution is given which in total should be 95662 packets. I am not getting a doc that explains how to interpret the above given O/P. For 64 it is .313 and 96 is .254. Are .313 and .254 the percentage of 64 and 96 sized packet? Can someone, please let me know logic and if possible share me reference link for it. With regards Kings
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