Serialization delay is a function of how long it will take to get X bits onto the wire at speed Y
And is simply X/Y So, a 1500-byte ping will take 214ms to be put on the wire at a line speed of 560000 bps (1500*8)/56000 = .214 So, you list the speed of the circuit.... 768000 The fragment size ... 960 So, (960*8)/768000 = 10 ms So, 384k would equal 5ms Jonathan On Wed, Apr 2, 2008 at 8:29 PM, jason sung <[EMAIL PROTECTED]> wrote: > Can someone confirm my calculations? I am trying to calculate delay based on > port speed and CIR. > > Port speed: 768 > CIR: 384 > > fragment size = 768 *10/8 = 960 > > delay = fragment size *8/ CIR > = 960*8/384 > = 20 ms > > 20 ms sounds too high though.... > > TIA
