Hi Mazin,

Thanks. I'm totally agreed with your calculation, but just to emphasize that
how you treat the remaining bandwidth in % calculation.
As long the *remaining* is *equally* shared, then i believe we got the
point.

And you got the point. :)

TIA
Shingei

On Fri, Oct 22, 2010 at 4:10 AM, Mazin Ahsan <[email protected]> wrote:

> Thanks Shingei,
>
> Lets say that 4:4 ratio shares the 50% bandwidth among the two queues.
> According to the task we also have to have 20% bandwidth with priority-queue
> .
>
> The 3750 have two input queues. If we are to give one queue priority with
> 20% bandwidth according to the question. Then we have to share the rest
> between the two queues equally, we are giving 4:4 ratio to the queues.
>
> Lets say we have Fasthethernet link
>
> Queue 1 : 20% Prioritized.   =============== 20Mbps
> Queue 1 : 50% Bandwidth of 80 Mbps======= 40Mbps
> Queue 2 : 50% Bandwidth of 80 Mbps======= 40Mbps
>
> Queue 1 will be  prioritized queue and will get priority upto 20% bandwidth
> after which the remaining of the traffic will be shared with the ratio of
> 4:4 . Meaning 50% to each queue.
>
>
> HTH
> Mazin
>
> -
> ---------------------------------
>
>
>
> Hi Greg,
>
> I think Amr is referring to the WB question that require the remaining
> bandwidth of 80% (after deducted the 20% for PQ on queue1) to be equally
> shared between Q1 and Q2.
> In this case, neither Q1 4/(4+4) nor Q2 4/(4+4) will get 50%. Q1 and Q2
> will
> get 40% each, i believe this achieve what the question asked which equally
> shared between the remaining bandwidth.
>
> If configured Q1 5/(5+5) and Q2 5/(5+5) and the result multiply by 80%, you
> will still get the 40% each queue, so mean it doesn't a matter what value u
> configured, as long both of them are same.
>
> For me is quite straight, if the question ask to disable the PQ, then
> n/(n+y) or y/(n+y) the valuable n and y can be ANY value that add up total
> to be 100, which mean it can be (25+75), (40+60)...etc.
> But if the the question asking to turn on PQ and equally shared the
> remaining bandwidth, i think the same value of n and y is applied.
>
> Please correct me if wrong.
> IMHO.
> Shingei.
>
>
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