.223 - .254 does equal 32 addresses .223 - .232 = 10 addresses .233 - .242 = 10 addresses .243 - .252 = 10 addresses .253 - .254 = 2 addresses
Regards, Jeff Rensink : Sr Instructor : iPexpert <http://www.ipexpert.com/> CCIE # 24834 :: Wireless / R&S :: World-Class Cisco Certification Training Direct: +1.810.326.1444 :: Free Videos <http://www.youtube.com/ipexpertinc> :: Free Training / Product Offerings <http://www.facebook.com/ipexpert> :: CCIE Blog <http://blog.ipexpert.com/> :: Twitter <http://www.twitter.com/ipexpert> On Sun, Dec 29, 2013 at 2:47 PM, Jay Killion (jakillio) <[email protected]>wrote: > Quick question… > > Requirement is - "For all IPv4 DHCP scopes, use the upper 32 device > addresses of the subnet." > > The solution excludes 10.10.x.1 – 10.10.x.222, but shouldn't the correct > exclusion actually be to .221? If it ends at .222 then the usable > addresses are .223 - .254, which equals 31 device addresses. > > Thanks - > > Jay Killion, CCIE #17873 R/S > > _______________________________________________ > Free CCIE R&S, Collaboration, Data Center, Wireless & Security Videos :: > > iPexpert on YouTube: www.youtube.com/ipexpertinc >
_______________________________________________ Free CCIE R&S, Collaboration, Data Center, Wireless & Security Videos :: iPexpert on YouTube: www.youtube.com/ipexpertinc
