Hi All,
I've been trying to solve this problem for a while now and just can't
get my head around this weird XSL business (Who comes up with a
language that only allows you to assign to a variable once?).
Given XML looking something like:
<Modifications>
<Modification>
<changeNumber>123<changeNumber>
<comment>changes for 123<comment>
<file>file1.cpp</file>
</Modification>
<Modification>
<changeNumber>123<changeNumber>
<comment>changes for 123<comment>
<file>file2.cpp</file>
</Modification>
<Modification>
<changeNumber>124<changeNumber>
<comment>changes for 124<comment>
<file>file1.cpp</file>
</Modification>
<Modification>
<changeNumber>125<changeNumber>
<comment>changes for 125<comment>
<file>file1.cpp</file>
</Modification>
<Modification>
<changeNumber>125<changeNumber>
<comment>changes for 125<comment>
<file>file2.cpp</file>
</Modification>
<Modifications>
I want to see a table looking like:
123 changes for 123
124 changes for 123
125 changes for 125
and not:
123 changes for 123
123 changes for 123
124 changes for 123
125 changes for 125
125 changes for 125
That is; I what to not render a row if the change number for the
current row being rendered is the same as that of the preceeding row.
The closest I have come in my solution so far is:
<xsl:for-each select="//modification">
<xsl:sort select="changeNumber" order="descending" data-
type="text" />
<xsl:if test="(position() = 1) or (changeNumber != preceding-
sibling::modification[1]/changeNumber)">
<tr>
<td class="table-text" valign="top"> <xsl:value-of
select="changeNumber"/> </td>
<td class="table-text" valign="top"> <xsl:value-of select="comment"/
> </td>
</tr>
</xsl:if>
</xsl:for-each>
But this seems to skip entries when I have long lists of
modifications.
So the challenge is layed down! Come on clever cloggs!
Please help,
Shaun
