Given inexact NCS, I would think that the systematic extinctions should be less extinguished at higher resolution. Is this correct?

Jacob

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Jacob Pearson Keller
Northwestern University
Medical Scientist Training Program
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----- Original Message ----- From: "Ian Tickle" <[email protected]>
To: <[email protected]>
Sent: Monday, December 15, 2008 1:03 PM
Subject: Re: [ccp4bb] About system absence in P4222?



Hi Lijun,

I take your point, and you're right I've confused someone else already! I made the NCS exact because a) I was using Eleanor's example (exactly) and was too lazy to make it inexact, and b) making it exact makes the point equally well as making it inexact (actually IMO better because it makes it very easy to distinguish pseudo-absences from accidentally weak reflections) - as long as you don't over-interpret the results!

So for anyone who's confused, my apologies, just imagine that the NCS translation isn't exact, and consequently the 'absences' won't be exactly zero. The point I was making is that NCS translations do not necessarily produce the same systematic absences (or pseudo-absences) as crystallographic translations.

Cheers

-- IAn

-----Original Message-----
From: Lijun Liu [mailto:[email protected]]
Sent: 15 December 2008 18:10
To: Ian Tickle
Cc: [email protected]
Subject: Re: [ccp4bb] About system absence in P4222?

Ian,

Your examples may cause more confusion, especially for those
beginners with symmetry.
In your P222 and P3 cases, an exact "NCS" (0, 0, 1/2) turns
to be an exact crystallographic
translation, which reduces the unit cell to a half while the
reciprocal unit cell gets doubled.  A
half of reflection were absent, including those listed as (0,
0, 2n+1).  This rule applies generally
to all non-centrosymmetric space groups (P1, P2, P3, P4, and
P6) with P-lattice when only having
one rotational symmetric element other than P1, and some
other space groups like P222.

(Pseudo) translational NCS' role in systematic
absences(weakness) is complicated.  However,
to do the math with
--------------

Plug the coordinates (x,y,z) and x+tx, Y+ty,
z+tz) into the


SF equation.

--------------
is exactly the only way to test it.

Lijun


On Dec 15, 2008, at 5:04 AM, Ian Tickle wrote:



But that only means that the SF contribution from that
pair of molecules in the unit cell is zero for (00l) l=odd
reflections.  Depending on the crystallographic symmetry
(e.g. if it were 3-fold or higher order) there may be other
pairs for which the SF contribution is non-zero for all (00l)
(but zero for the the odd orders in some other line that is
symmetry-equivalent to (00l)).

So for example I did a test with 2 mols in the a.u.
related by an exact (0,0,1/2) NCS translation in P222:

   h   k   l       Fcalc   phicalc
   0   0   1        0.00    180.00
   0   0   2     5120.88    180.00
   0   0   3        0.00    180.00
   0   0   4     1273.09      0.00
   0   0   5        0.01      0.00
   0   0   6      260.21    180.00
   0   0   7        0.00    180.00
   0   0   8       39.42    180.00
   0   0   9        0.01      0.00
   0   0  10       43.19      0.00
   0   0  11        0.00    180.00
   0   0  12      118.59    180.00
   0   0  13        0.01      0.00
   0   0  14      120.89    180.00
   0   0  15        0.01      0.00

(00l) l odd are definitely absent here! - because none
of the crystallographic 2-folds affect the (0,0,1/2) translation.

Then I generated 2 mols in the a.u. related by the
(1/2,0,0) NCS translation in P4 to get the (h00) line (note
that the 4-fold along c would not affect a c-axis translation):

   1   0   0    25189.10      0.00
   2   0   0      200.09      0.00
   3   0   0    14404.46    180.00
   4   0   0    12608.60    180.00
   5   0   0     4669.64    180.00
   6   0   0      748.81      0.00
   7   0   0     3184.06      0.00
   8   0   0     3858.87      0.00
   9   0   0     2578.38      0.00
  10   0   0      382.61      0.00
  11   0   0      683.43    180.00
  12   0   0      444.89    180.00
  13   0   0      236.65    180.00
  14   0   0      352.46    180.00
  15   0   0        5.62      0.00

No absences!  The 4-fold generates a pair of molecules
related by the (0,1/2,0), not the (1/2,0,0) translation.  So
Eleanor is right only in specific cases, Ronald is right in
the general case.

As an aside, while I was verifying this, I think I
found a problem with the P3 specific SF calculation in SFALL.
 Here's what I get for 2 mols in the a.u. related by an exact
(0,0,1/2) NCS translation in P3 using the default P3 specific routine:

   0   0   1        8.24   -175.63
   0   0   2     7339.05    121.46
   0   0   3       27.32    125.92
   0   0   4      949.76    -10.37
   0   0   5       39.10   -103.39
   0   0   6      461.79   -115.99
   0   0   7       19.18     61.53
   0   0   8      219.72    -96.80
   0   0   9       66.51   -174.45
   0   0  10      288.25    -86.65

Now if I use the P1 routine (SFSG 1):

   0   0   1        0.00    165.96
   0   0   2     7343.28    121.51
   0   0   3        0.00    -24.58
   0   0   4      974.19    -13.35
   0   0   5        0.00   -155.29
   0   0   6      438.79   -115.60
   0   0   7        0.01    133.49
   0   0   8      226.07    -97.44
   0   0   9        0.01   -101.82
   0   0  10      291.15    -83.96

The 3-fold along c should not generate any pairs not
related by the (0,0,1/2) NCS translation, so there should be
(00l) l odd absences in this case.  So something wrong here!
Personally I always use the P1 routines, why take a chance
just to shave a few secs off the run time? (note that ccp4i
uses the default, i.e. the space-group specific routines).

Cheers

-- Ian



-----Original Message-----


From: [email protected]


[mailto:[email protected]] On Behalf
Of Eleanor Dodson


Sent: 15 December 2008 09:56


To: Ronald E Stenkamp


Cc: [email protected]


Subject: Re: [ccp4bb] About system absence in P4222?



Plug the coordinates (x,y,z) and x+tx, Y+ty,
z+tz) into the


SF equation.


If the translation component along c is 0.5
say,   then all the 00l


reflections for l=2n+1 will be absent.



Eleanor




Ronald E Stenkamp wrote:


Hi.



Non-crystallographic symmetry (NCS)
doesn't apply to the entire


crystal, so how can it give rise to
systematic absences?  I know it


can give rise to systematically weak classes of


reflections, but they


aren't entirely absent.



Ron



On Thu, 11 Dec 2008, Winter, G (Graeme) wrote:



One of the many facilities in
pointless is to search for


absences and


provide a list of likely
spacegroup choices based on the


results. It


includes adjustments for
neighbouring spots to address one of


Eleanor's concerns. NCS can
cause reflections to be systematically


absent too.



The program can be found on the
ccp4 prerelease pages or on the


pointless ftp site.



Cheers,



Graeme



-----Original Message-----


From: CCP4 bulletin board
[mailto:[email protected]]


On Behalf Of


Eleanor Dodson


Sent: 11 December 2008 09:41


To: [email protected]


Subject: Re: [ccp4bb] About
system absence in P4222?



劉家欣(NTHU) wrote:


Dear All:



We have a crystl with P4222 sg.


All statistics look fine.


However, there is a
system absense in l axis.


Any body have
experiences on that?


Any suggestions would
be high appreciated.



jaishin



can you give more details, eg
all reflections along the particular


axis..


Things like ice rings or
overlapping intensity from a next


neighbour


getting integrated
inapropriately can cause anomalies..


Eleanor










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Lijun Liu, PhD
Institute of Molecular Biology
HHMI & Department of Physics
University of Oregon
Eugene, OR 97403
541-346-5176
http://www.uoregon.edu/~liulj/






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