Hi Jeffrey

Re-indexing this in the conventional setting (i.e. beta nearest to 90 -
for reasons no-one has yet been able to explain to me the standard d.p.
programs do not make this choice automatically!) gives you space group
I2 with cell:

a=58.1  b=95.8  c=76.67  beta=90.24

With beta now so close to 90, twinning is quite likely.  Also it's quite
likely that this cell shows the relationship to I222 much more clearly
than the C2 one, and if it is twinned the 2-fold axes of the I-centred
orthorhombic cell will almost certainly be the twinning axes in the I2
cell.

Finally I would not base any determination on the *centric* moments,
simply because there are so few centric reflections in monoclinic!  You
must look at the *acentric* moments.  Also look at the stats from the
detwin program using the re-indexed data with the h,-k,-l or -h,-k,l
twin operators; this gives you an estimate of the twin fraction: actual
detwinning of the data may or may not prove useful!

HTH

-- Ian

> -----Original Message-----
> From: [email protected] [mailto:[email protected]]
On
> Behalf Of Jeffrey D Brodin
> Sent: 16 June 2009 17:24
> To: [email protected]
> Subject: Possible C2 Twinning
> 
> Dear ccp4bb,
> 
> I've recently run into a problem refining a crystal structure that I
> indexed and performed a molecular replacement on as C2.  The unit cell
> dimensions are a=96, b=95.8, c=58.1 and beta=127; Rmrg=.195.  The data
go
> down to a resolution of 2.8 angstroms.  The data also index in I222,
but
> scaling statistics are worse (Rmrg = .598) and Molrep does not find an
> acceptable solution.  Using the C2 space group Molrep finds a solution
> with the expected 4 monomers (protein size is ~12.5kd) in the
asymmetric
> unit, but I have only been able to refine it to an R/Rfree of 33/37.
The
> asymmetric unit consists of two dimers, and performing a two-fold
rotation
> around an axis perpendicular to the helices of the dimers generates
the
> tetramer that we would expect from other experimental data.  Also, the
> backbone density for two of the monomers is much worse than normal.
> Truncate shows possible twinning in that the 4th centric moment of E
has
> an observed value of 2, which is what would be expected for a perfect
twin
> (actual expected value is 3) and the first and third centric moments
are
> .87 and 1.45 respectively, with expected values of .8 and 1.6 and .89
and
> 1.33 for perfect twins.  I am new to resolving twinning issues and was
> wondering if anyone has any ideas as to whether I may have the space
group
> wrong or if there is a twinning operator that I could use to resolve
this
> issue.  Thanks in advance for your help,
> 
> Jeff



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