Hi Roger,

You are correct, that *conceptually* the contribution to the target function is 
sum(w (|d|-|dcurrent|)^2)… however this is not actually applied to the target 
function. The target function remains unchanged. Only the 2nd derivative is 
affected by the jelly-body restraints.

Also, note that the refmac5 ccp4i interface quotes: "use jelly body refinement 
with sigma 0.02". You mention that "bigger w, more rigid jellyfish". This is 
correct. However, note that w is inversely related to sigma, thus it should be 
acknowledged that "smaller sigma, more rigid jellyfish"…

Also, note that the utility of such regularisers is greater when the effective 
observation-to-parameter ratio is worse, i.e. at lower resolutions. At this 
stage, it is not certain exactly what the resolution threshold is such that 
jelly-body restraints are useful. I can envisage that it not only depends on 
the resolution, but also on the quality (or noisiness) of the data. I am sure 
that there are 2.9A datasets out there that would benefit from such 
regularisers.

Cheers
Rob



On 23 Aug 2012, at 19:31, Roger Rowlett wrote:

> Garib gave a nice description of jelly-body refinement at the ACA meeting. 
> IIRC from his talk, conceptually jelly-body refinment is the equivalent of 
> adding "springs" between atoms within a certain radius of each other that 
> restrain their movement during refinement. The restraints contribute to the 
> target function curvature. The weight factor describes the contribution of 
> the restraints to the overall target function. If w=1 and and the radius of 
> atoms considered was infinity, you would have rigid body refinment. If w=0 
> you have normal uncontrained refinment. The REFMAC defaults are 4.2 A for the 
> constraints radius, and 0.02 for the weighting factor. If I understand it 
> correctly, it's basically like a slightly flexible rigid body refinement. 
> Bigger w, more rigid jellyfish. (Someone will correct me if I have this 
> wrong.)
> 
> Mathematically, the contribution to the target function is sum(w 
> (|d|-|dcurrent|)^2)  where is d is a measure of the distances between atom 
> pairs within a certain radius. The value d is the new distances and dcurrent 
> is the old distances. The value w is the weighting factor.
> 
> I have a recently obtained 2.9A dataset for which this approach might be 
> interesting to try and see how it works compared to the usual unrestrained 
> refinement and/or TLS, etc.
> 
> Cheers,
> 
> _______________________________________
> Roger S. Rowlett
> Gordon & Dorothy Kline Professor
> Department of Chemistry
> Colgate University
> 13 Oak Drive
> Hamilton, NY 13346
> 
> tel: (315)-228-7245
> ofc: (315)-228-7395
> fax: (315)-228-7935
> email: [email protected]
> 
> On 8/23/2012 1:27 PM, Nathan Pollock wrote:
>> Dear experts,
>> 
>> Could someone explain what it is exactly that jelly body refinement
>> does? I think that I understand it intuitively but want to make sure.
>> In the same vein, what does jelly body refinement sigma parameter
>> control? I.e., in comparison to the default sigma = 0.02, does sigma =
>> 0.1 make body more or less like a jelly fish?
>> 
>> Thanks!
>> 
>> - Nate

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