>in your other posting, you gave the example (using the notation of the detwin documentation):
DANOTw(h1) = 52 DANOTw(h2) = 28 and if you use the formulas that you cite below, you get the true values back: DANOtrue(h1) = (0.6*52 - 0.4*28)/(1-0.8) = 100 DANOtrue(h2) = (0.6*28 - 0.4*52)/(1-0.8) = -20 So then, what's problematic? ====================== Nothing--I think you're right, and my intuition was wrong. Thanks for correcting my mis-statement. What would come of detwinning Dano rather than I+/-? I wonder, like you, whether anything would be gained or lost? JPK
